Question

answer and show work and ill give brainliest, Steven has one bag that contains three table-tennis balls numbered 1, 2, and 3. He also has a second bag that contains four table-tennis balls lettered A, B, C, and D.

Answer 1

Answer:

B

Step-by-step explanation:

Assuming Part A is the situation where the bags aren't merged, the probability of drawing a "1" followed by a "B" is (1/3)(1/4) or 1/12. This is because you have a 1/3 chance of getting a "1" and a 1/4 chance of getting a "B".

Now if we merge the bags, we have a 1/7 chance of getting a "1". We then have a 1/6 chance of getting a "B". This is because after we complete the first draw, the bag only has 6 remaining not 7. This gives us a probability of (1/7)(1/6) or 1/42.

So we know the probability will change so C is wrong. In both scenarios, we draw two balls anyways so A is wrong.

This leaves B, which is supported by the reasoning presented above.