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grin007 [14]
2 years ago
13

On your family plan you have 6 GB data limit each month you were your brother he cheats 0.75 GB each month and your mother and f

ather split the rest even like to stay under the limit how much data can your mother and father each use
Mathematics
1 answer:
chubhunter [2.5K]2 years ago
6 0

Answer: See explanation

Step-by-step explanation:

Your question isn't well written but I guess you meant that 0.75gb was shared at first. This means that the father and mother will share:

= 6 - 0.75

= 5.25

Therefore, each of them will use:

= 5.25 / 2

= 2.625gb

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Simplify each only using positive exponents:<br> 2x^-3 • 4x^2<br> 2x^4 • 4x^-3<br> 2x^3y^-3 • 2x
erica [24]
<h2>Answer:</h2>

\frac{2}{x}

\frac{x}{2}

\frac{4x^4}{y^3}

<h2>Step-by-step explanation:</h2>

a. 2x^-3 • 4x^2

To solve this using only positive exponents, follow these steps:

i. Rewrite the expression in a clearer form

2x⁻³ . 4x²

ii. The position of the term with negative exponent is changed from denominator to numerator or numerator to denominator depending on its initial position. If it is at the numerator, it is moved to the denominator. If otherwise it is at the denominator, it is moved to the numerator. When this is done, the negative exponent is changed to positive.

In our case, the first term has a negative exponent and it is at the numerator. We therefore move it to the denominator and change the negative exponent to  positive as follows;

\frac{1}{2x^3} . 4x^2

iii. We then solve the result as follows;

\frac{1}{2x^3} . 4x^2 = \frac{2}{x}

Therefore, 2x⁻³ . 4x² = \frac{2}{x}

b. 2x^4 • 4x^-3

i. Rewrite as follows;

2x⁴ . 4x⁻³

ii. The second term has a negative exponent, therefore swap its position and change the negative exponent to a positive one.

2x^4 . \frac{1}{4x^3}

iii. Now solve by cancelling out common terms in the numerator and denominator. So we have;

\frac{x}{2}

Therefore, 2x⁴ . 4x⁻³ = \frac{x}{2}

c. 2x^3y^-3 • 2x

i. Rewrite as follows;

2x³y⁻³ . 2x

ii. Change position of terms with negative exponents;

2x^3.\frac{1}{y^3} .2x

iii. Now solve;

\frac{4x^4}{y^3}

Therefore, 2x³y⁻³ . 2x = \frac{4x^4}{y^3}

8 0
3 years ago
Help meeeeeeeeeeeeeeeeeeeeeeeee
IRINA_888 [86]

Answer:

118.75

Step-by-step explanation:

47.50 multiplied by 2.5 would equal 118.75

ur welcome :)

3 0
3 years ago
Read 2 more answers
The roots of the equation x^2+px+q=0 are -1 and 3. what is the value of q?
Alex787 [66]

Answer:

3

Step-by-step explanation:

6 0
3 years ago
The value of 1 tenth is less the value of 3 tenth
Lesechka [4]

Answer:

True, 3 tenths is closer to one whole

Step-by-step explanation:

                              ↓                                                                 ↓

8 0
3 years ago
Find the mean absolute deviation of the set of data 3,8,10,12,15
inn [45]

Answer:

3.28

Step-by-step explanation:

find the mean of all the numbers

3 + 8 + 10 + 12 + 15 = 48

48/5=9.6

so the mean of all the numbers is 9.6

now subtract 9.6 from all the numbers

|3 - 9.6| = 6.6

|8 - 9.6| = 1.6

|10 - 9.6| = .4

|12 - 9.6| = 2.4

|15 - 9.6| = 5.4

Find the mean/average of the new values

6.6 + 1.6 + .4 + 2.4 + 5.4 = 16.4

16.4/5  = 3.28

6 0
3 years ago
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