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aleksklad [387]
2 years ago
15

Surveys were sent to a random sample of owners of all-wheel-drive (AWD) vehicles and to a random sample of owners of front-wheel

-drive (FWD) vehicles. The proportion of owners who were satisfied with their vehicles was recorded for each sample. The sample proportions were used to construct the 95 percent confidence interval for a difference in population proportions (FWD minus AWD) for satisfied owners. The interval is given as (−0.01,0.12). A car company believes that the proportion of satisfied owners of AWD vehicles differs from the proportion of satisfied owners of FWD vehicles. Does the confidence interval provide evidence that this belief is plausible?
Mathematics
1 answer:
salantis [7]2 years ago
8 0

Answer:

No, the confidence interval does not provide evidence that this belief is plausible as the confidence interval range contains the null value (0)

Step-by-step explanation:

Given that the confidence interval for the mean difference of AWD and FWD vehicles is :

(−0.01,0.12)

When defining the hypothesis for mean difference :

H0 : μ1 - μ2 = 0

H1 : μ1 - μ2 ≠ 0

Using the confidence interval result, reject the Null if the confidence interval value at the given α - level does not contain 0 ; otherwise fail to reject the Null ;

Since the (−0.01,0.12) contains 0 ; then we fail to reject the Null and conclude that there is no statistically significant difference between the two groups

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A baseball collector took inventory of all of his baseball cards along with the value of each card. The box plot represents the
love history [14]

Answer: less than 25%

Step-by-step explanation:

The box plot can be read as follows:

The first black dot is the minimum value.

The first half of the rectangle is the lower quartile.

The line that separates the two rectangles is the median.

The second half of the rectangle is the upper quartile

The final point is the maximum.

Knowing that each quartile represents about the 25% of the elements for the set, we can see that both lower and upper quartile (and the 25% of the elements that come after the upper quartile) cost more than $45.

Then we know that at least the (25% + 25% + 25%) = 75% of the cards in the collection cost more than $45.

And we also have elements that are not in the lower quartile that cost more than $45, but we can not determine the percentage that they represent.

So we can only conclude that more than the 75% of the collection costs more than $45.

Now we want to know the percentage of the baseball cards valued at less than $45.

So if more than 75% is valued at more than $45.

Then less than 25% is valued at less than $25.

8 0
3 years ago
Is this true or no plz help
il63 [147K]
Im pretty sure its No.
7 0
3 years ago
HELP I NEED HELP ASAP
lilavasa [31]

Answer:

I think it its

Step-by-step explanation:

C if its wrong sorry

8 0
3 years ago
Help please
Len [333]

Answer:

Ques 1)  1440°

Ques 2) 4000

Ques 3) 33

Step-by-step explanation:

Ques 1)

The sum of the measures of the angles in degrees of a polygon with 'n' sides is given by: 180×(n - 2).

Now we have to find the sum of the measures the angles of a polygon with 10 sides.

i.e. n=10

Hence the value of the expression 180×(n-2) when n=10 is given by:

180×(10-2)=180×8=1440.

Hence, the sum of measure of the angles of a polygon with 10 sides is: 1440°.

Ques 2)

The Expression 500v gives the number of points a player earns for completing v voyages in video game.

We are asked to find the number of points earned for completing 8 voyages.

i.e. v=8 the value of 500v will be 500×8=4000.

Hence, 4000 points are earned for completing 8 voyages.

Ques 3)

we have to find the value of the question as given in the figure:

7x+y+16 for x=2 and y=3.

Hence, we find the value of the expression:

7×2+3+16=33.

Hence, the value of the expression is 33.




8 0
2 years ago
How hard must someone pull on the unkown line and inwhat direction to keep the knot from moving ​
dolphi86 [110]

Answer:

4.4N, 263.4°

Step-by-step explanation:

The sum of all forces must add to zero:

The forces in the x-plane:

∑F = 3N + (cos 120°)*5N + x = 0

x = -(3N + (cos 120°)*5N)

x = -0.5N

The forces in the y-plane:

∑F = (sin 120°)*5N + y = 0

y = -(sin 120°)*5N = -√(3/4)*5N = -4.3N

The magnitude of the unknown force U is:

U = √(x² + y²) = √19 = 4.4N

The direction is given by:

tanФ = y/x

Ф = 263.4°

4 0
3 years ago
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