Answer:
(6,-1)
Solve for the first varible in one of the equations, then subsititue the other equation.
since by the provided tickmarks WE ≅ ER, and QE ≅ ET, then both triangles are congruent by LL theorem, Leg Leg.
anyhow, since those legs are congruent, their hypotenuses must also be congruents, and we could use the HL theorem as well.
Answer:
4
Step-by-step explanation:
Please let me know if you want me to add an explanation as to why this is the answer. I can definitely do that, I just don’t want to waste my time in case you don’t want me to :)
Answer:
8k
Step-by-step explanation:
1. Simplify: -k + 8k
2. -k + 8k = 7k
In the original graph, R (0,3), S(3,3), T(4, -1) and Q(0, 1)
Reflecting it across y=-1, which is a horizontal line going through the point T, all the x coordinates stay the same,
the new confidantes are : R'(0, -5), S'(3, -5), T'(4, -1), Q(0', -3) (Notice; T stays where it is now, because it is right now the line y=-1)
Locate these new points, you have your graph.
