True. Both methods correctly verify the trig identity
27.2h÷1h=27.2
500.48m in 27.2h
(÷27.2)
18.4 in 1h
Ans: 18.4m/h
a) 70.1 m
The ball is moving by uniformly accelerated motion, with constant acceleration
(acceleration due to gravity) towards the ground. The height of the ball at time t is given by the equation

where
is the height of the ball at time t=0. Substituting t=1 s, we can find the height of the ball 1 seconds after it has been dropped:

b) 3.9 s
We can still use the same equation we used in the previous part of the problem:

This time, we want to find the time t at which the ball hits the ground, which means the time t at which h(t)=0. So we have

And solving for t we find

The solution 92 is how tall the basil plant becomes in two weeks after he starts recording its height.
There's 14 days in two weeks.
There's no equation shown, but I suppose it was like this:
5x+22=92
But once you insert 14 days in the equation, it'll become:
5(14)+22=92
70+22=92
92=92