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Semenov [28]
3 years ago
11

HELPPPPP A pearlfish spends the day inside the alimentary tract, or intestines, of a sea cucumber. The fish emerges from the sea

cucumber at night to feed on small crustaceans. The pearlfish gets a safe place to live. The sea cucumber does not gain anything from the relationship, nor is it harmed. This is similar to the relationship between which of the following organisms?
A) Fox and bunnies, and lions and zebras.

B) Tapeworms in the gut of animals, and lice on the head of humans.

C) The barnacles that attach on whales and the shuckerfish that travel together with sharks.

D) Bees and plants or sea anemonies and clownfish.
Chemistry
1 answer:
Makovka662 [10]3 years ago
5 0

Answer:

D) Bees and plants or sea anemonies and clownfish.

i think..

Explanation:

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A 50.0 mL sample of waste process water from a food processing plant weighing 50.1 g was placed in a properly prepared crucible
RideAnS [48]

Answer:

TS (total solid, mg/L) = 57,174 mg/L

VS (volatile solid, mg/L) = 24,088 mg/L

Explanation:

First step to solve this problem is to know data and questions:

Data:

Sample volume = 50 mL

Sample weight = 50.1 g

P1 (weight empty crucible) = 17.1234 g

P2 (weight after drying a 103º in oven) = 19.9821  g

P3 (weight after incinatrion 550º) = 18.7777 g

Questions:

TS = ?  

VS = ?

Formula:

We need to use formulas to calculate total solid (TS) and volatile solid (VS), these are:

TS =\frac{(P2-P1)*\frac{1,000 mg}{1g} }{Sample volumen (L)}

VS = \frac{(P2-P3)*\frac{1,000 mg}{1g} }{Sample volume (L)}

We have to transform mL to L so we will divide mL by 1,000 the sample volume:

Sample Volumen (L) = 50 mL * \frac{1L}{1,000 mL} = 0.05 L

In the formula the value of 1,000 results by the convertion factor to transform grams to miligrams (we have to multiplie by 1,000)

Now we need to replace data on previous formulas and we will get TS and VS expressed in mg/L:

TS = \frac{(19.9821 g-17.1234g)*\frac{1,000 mg}{1g} }{0.05L} = 57,174mg/L

VS = \frac{(19.9821g-18.7777g)*\frac{1,000mg}{1g} }{0.05L}=24,088 mg/L

We divide TS and VS formula by sample volume because the exercise is asking us to express the results in mg/L.

4 0
3 years ago
What is the empirical formula for a substance that contains 3.730% hydrogen, 44.44% carbon, and 51.83% nitrogen by mass?\?
Vlada [557]

Given data:

Hydrogen (H) = 3.730 % by mass

Carbon (C) = 44.44%

Nitrogen (N) = 51.83 %

This means that if  the sample weighs 100 g then:

Mass of H = 3.730 g

Mass of C = 44.44 g

Mass of N = 51.83 g

Now, calculate the # moles of each element:

# moles of H = 3.730 g/ 1 g.mole-1 = 3.730 moles

# moles of C = 44.44/12 = 3.703 moles

# moles of N = 51.83/14 = 3.702 moles

Divide by the lowest # moles:

H = 3.730/3.702  = 1

C = 3.703/3.702 = 1

N = 3.702/3.702 = 1

Empirical Formula = HCN

3 0
3 years ago
All chemicals should be stored in ?
netineya [11]

im a container or a glass

5 0
3 years ago
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Predict the formula for Ba+2 and S-2
prisoha [69]
I believe it is BaS I hope this helps! 
3 0
3 years ago
If the pOH of a solution is 9.1, what is the concentration of OH- ions in that solution?
Amiraneli [1.4K]

Answer:

7.9432*10^-10 or 10^-9.1

Explanation:

pOH=-log[OH]

4 0
3 years ago
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