Answer:
Option C. 0.23 molar
Explanation:
The following data were obtained from the question given:
C1 = 0.5 M
V1 = 340mL
V2 = since 400mL was added to the original volume, therefore = 340 + 400 = 740mL
C2 =?
The concentration of the diluted solution can be calculated by using the following:
C1V1 = C2V2
0.5 x 340 = C2 x 740
Divide both side by 740
C2 = (0.5 x 340) / 740
C2 = 0.23M
Therefore, the new concentration of the solution is 0.23M
You need to look at the electronegativity and decide wheter the difference of both of the numbers are significant enough to form a polar bond
M₁V₁=M₂V₂
65 x M₁ = 16.8 x 0.5
M₁ = 0.129
65 x M₁ = 18.2 x 0.5
M₁ = 0.14
65 x M₁ = 17.35 x 0.5
M₁ = 0.133
Average = 0.129 + 0.14 + 0.133 = 0.134 M
Answer:
1m×268.0L/22.4L=11.9m
Explanation:
there are 11.9 moles of nitrogen monoxide are present
0.680 L/min is equivalent to 1.13 \× 10⁴ μL/min.
In order to convert 0.680 L/min to units of microliters per hour, we need the following conversion factors:
<u>0.680 L/min, expressed in units of microliters per hour, is:</u>
0.680 L/min is equivalent to 1.13 \× 10⁴ μL/min.
You can learn more about unit conversions here:
brainly.com/question/11543684
