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ruslelena [56]
3 years ago
13

The transitional phrases "most significantly" and "least significantly" are used commonly. Which organizational structure is mos

t likely to use these transitional words?
A. spatial

B. order of importance

C. logical

D. sequential
Mathematics
2 answers:
Alexandra [31]3 years ago
7 0

The answer is B. Order of importance


Anvisha [2.4K]3 years ago
4 0
I think it’s d I’m not sure but if I got it wrong I’m sorry
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The proof for the product property of logarithms requires simplifying the expression logb(bx y) to x y. Which property is used t
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You can use the properties of logarithm to derive the simplified form of the given expression.

The simplification of the given expression requires the given below properties of logarithm

  • log_a(b^c) = c \times log_a(b)\\\\
  • log_b(b) = 1

<h3>What is logarithm and some of its useful properties?</h3>

When you raise a number with an exponent, there comes a result.

Lets say you get

a^b = c

Then, you can write 'b' in terms of 'a' and 'c' using logarithm as follows

  • b = log_a(c)

Some properties of logarithm are:

log_a(b) = log_a(c) \implies b = c\\\\\log_a(b) + log_a(c) = log_a(b \times c)\\\\log_a(b) - log_a(c) = log_a(\frac{b}{c})\\\\log_a(b^c) = c \times log_a(b)\\\\log_b(b) = 1

<h3>Using the above properties, to get to the simplified form of the given expression</h3>

The given expression is

log_b(b^{x+y})

Using the property log_a(b^c) = c \times log_a(b)\\\\, we get

log_b(b^{x+y}) = (x+y)\times log_b(b)

Using the property log_b(b) = 1, we get

log_b(b^{x+y}) = (x+y)\times log_b(b) = (x+y) \times 1 = x + y

Thus,

The simplification of the given expression requires the given below properties of logarithm

  • log_a(b^c) = c \times log_a(b)\\\\
  • log_b(b) = 1

Learn more about logarithms here:

brainly.com/question/20835449

3 0
2 years ago
Read 2 more answers
9. Calcule el valor de la fuerza que experimenta un ascensor cuando levanta 150 kg en los siguientes casos: a) Cuando asciende c
GenaCL600 [577]

Answer:

a) La fuerza neta que experimenta un ascensor cuando asciende con una aceleración de 4 metros por segundo al cuadrado es 600 newtons hacia arriba.

b) La fuerza neta que experimenta un ascensor cuando desciende con una aceleración de 6 metros por segundo al cuadrado es 900 newtons hacia abajo.

c) Por la fuerza de tensión sobre el cable del ascensor.

Step-by-step explanation:

a) La fuerza neta experimentada por el ascensor (F), en newtons, es:

F = m\cdot a (1)

Donde:

m - Masa, en kilogramos.

a - Aceleración, en metros por segundo cuadrado.

Si sabemos que m = 150\,kg y a = 4\,\frac{m}{s^{2}}, entonces la fuerza neta del ascensor es:

F = m\cdot a

F = 600\,N

La fuerza neta que experimenta un ascensor cuando asciende con una aceleración de 4 metros por segundo al cuadrado es 600 newtons hacia arriba.

b) Si sabemos que m = 150\,kg y a = -6\,\frac{m}{s^{2}}, entonces la fuerza neta del ascensor es:

F = m\cdot a

F = -900\,N

La fuerza neta que experimenta un ascensor cuando desciende con una aceleración de 6 metros por segundo al cuadrado es 900 newtons hacia abajo.

c) De manera simplificada, el ascensor experimenta dos fuerzas que definen la fuerza y aceleración netas: (i) La fuerza de tensión sobre el cable que traslada el ascensor y el peso total del ascensor, opuesta a la anterior y en función de la aceleración gravitacional. Puesto que la masa no varía en ningún caso, se concluye que el peso es constante, entonces la diferencia de valores se debe a la fuerza por tensión del cable. En el descenso, es fuerza es menor que en el ascenso.

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