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2 years ago

Can cubic units be used to measure weight??

Mathematics

1 answer:

user100 [1]2 years ago

3 0

Answer:

No, they can't.

Step-by-step explanation:

In geometry, cubic units can be defined as the units used to measure volume. The volume of a unit cube whose length, width and height are 1 unit each is 1 cubic unit. The length, width and height of the rectangular prism can be measured by counting the number of unit cubes.

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There are 120 planes on an airfield. If 75% of the planes take off, how many planes took off?

Soloha48 [4]

Answer:

You have to do 120 divided by 0.75 use a calculator

Step-by-step explanation:

7 0

3 years ago

Could anybody help with this question? My teacher didn’t give a review so I’m not sure what to do. Any help is appreciated!

Allisa [31]

Answer: 6

Step-by-step explanation: set the equations equal to each other then solve. plug that number into the equation for AB

8 0

3 years ago

2+2=??? PLEASE HELP ME THIS IS SO HARD PLEASEEE!!!!!

fiasKO [112]

Answer: 2 + 2 = 4

Step-by-step explanation: Let's say you have 2 cars, and you friend has 2 cars, for your birthday, your friend gives you his 2 cars, so now in total you have 4 cars, hope this helped! -Mason

4 0

3 years ago

What is the maximum volume in cubic inches of an open box to be made from a 12-inch by 16-inch piece of cardboard by cutting out

Romashka-Z-Leto [24]

If you start with a 12x16 rectangle and cut square with side length x, when you bend the sides you'll have an inner rectangle with sides $12-2x$ and $16-2x$ , and a height of x.

So, the volume will be given by the product of the dimensions, i.e.

$(12-2x)(16-2x)x = 4x^3-56x^2+192x$

The derivative of this function is

$12x^2-112x+192$

and it equals zero if and only if

$12x^2-112x+192=0 \iff x = \dfrac{14\pm 2\sqrt{13}}{3}$

If we evaluate the volume function at these points, we have

$f\left(\dfrac{14-2\sqrt{13}}{3}\right) = \dfrac{64}{27}(35+13\sqrt{13})> f\left(\dfrac{14-2\sqrt{13}}{3}\right) = -\dfrac{64}{27}(13\sqrt{13}-35)$

So, the maximum volume is given if you cut a square with side length

$x=\dfrac{14-2\sqrt{13}}{3}\approx 2.7$

5 0

3 years ago

Type the correct answer in each box. A circle is centered at the point (5, -4) and passes through the point (-3, 2). The equatio

Galina-37 [17]

Answer:

$(x+ \boxed{-5})^2+(y+\boxed4)^2=\boxed{100}$

Step-by-step explanation:

Given:

Center of circle is at (5, -4).

A point on the circle is $(x_1,y_1)=(-3, 2)$

Equation of a circle with center $(h,k)$ and radius 'r' is given as:

$(x-h)^2+(y-k)^2=r^2$

Here, $(h,k)=(5,-4)$

Radius of a circle is equal to the distance of point on the circle from the center of the circle and is given using the distance formula for square of the distance as:

$r^2=(h-x_1)^2+(k-y_1)^2$

Using distance formula for the points (5, -4) and (-3, 2), we get

$r^2=(5-(-3))^2+(-4-2)^2\\r^2=(5+3)^2+(-6)^2\\r^2=8^2+6^2\\r^2=64+36=100$

Therefore, the equation of the circle is:

$(x-5)^2+(y-(-4))^2=100\\(x-5)^2+(y+4)^2=100$

Now, rewriting it in the form asked in the question, we get

$(x+ \boxed{-5})^2+(y+\boxed4)^2=\boxed{100}$

4 0

3 years ago