What other information is needed to prove that the two triangles congruent by SAS?
1 answer:
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Let KLMN be a trapezoid (see added picture). From the point M put down the trapezoid height MP, then quadrilateral KLMP is square and KP=MP=10.
A triangle MPN is right and <span>isosceles, because
</span>m∠N=45^{0}, m∠P=90^{0}, so m∠M=180^{0}-45^{0}-90^{0}=45^{0}.Then PN=MP=10.
The ttapezoid side KN consists of two parts KP and PN, each of them is equal to 10, then KN=20 units.
Area of KLMN is egual to
sq. units.
A triangle MPN is right and <span>isosceles, because
</span>m∠N=45^{0}, m∠P=90^{0}, so m∠M=180^{0}-45^{0}-90^{0}=45^{0}.Then PN=MP=10.
The ttapezoid side KN consists of two parts KP and PN, each of them is equal to 10, then KN=20 units.
Area of KLMN is egual to
Answer:
D. 0° to 90°
Step-by-step explanation:
If we see curve of sin(o) on coordinate, we will notice that value of sin curve increases from 0 to 90 degrees and then decreases from 90 to 180 degrees.
Hence option D is correct.
Alternatively
we see that
sin 0 = 0
sin 30 = 1/2
sin 45 = 1/
sin 60 =
sin 90 = 1
Thus, we see that value of sin is increasing from 0 to 90
now lets see value of sin from 90 to 180
sin 90 = 1
sin 120 =
sin 135 = 1/
sin 150 = 1/2
sin 180 = 0
Thus, we see that value of sin is decreasing from 90 to 180.