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Otrada [13]
3 years ago
7

What is the common ratio in the geometric sequence: 12, 3, 3/4 …….

Mathematics
1 answer:
Mashutka [201]3 years ago
6 0

Answer:

1/4

Step-by-step explanation:

to find the ratio:

3/12 : (3/4)/3

1/4 : 1/4

term2/ term1 : term2/term3

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Rectangle WXYZ was dilated to create W'X'Y'Z'.
Snezhnost [94]

You did not attach any picture to solve this problem. We cannot calculate for the value W’X’ without the correct illustrations. However, I think I found the correct one (see attached), please attach it next time.

So the first thing we have to do is to calculate for the dilation factor. Taking point G as the reference point, we can see that the distance of point G from rectangle W’X’Y’Z’ is 1.5 while the distance from rectangle WXYZ is (1.5 + 7.5), therefore the dilation factor to use is:

dilation factor = 1.5 / (1.5 + 7.5) = 1.5 / 9 = 1/6

 

Since WX has an initial measure of 3 units, therefore the measure of W’X’ is:

W’X’ = 3 units * (1/6) = 0.5 units

 

Answer:

<span>0.5 units</span>

4 0
3 years ago
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24/10 as a decimal on a math paper
11Alexandr11 [23.1K]

Answer:

2.40

Step-by-step explanation:

7 0
3 years ago
What is the constant of proportionality between y and x in the graph? (WILL MARK BRAINLIST IF RIGHT!)
sweet [91]

Answer:

2

Step-by-step explanation:

4 can be divided by 2 & 2 can be divided by 2

5 0
3 years ago
Let A = -4k+ 3 and B = 3k +17. If A = B, then what is the value of k?​
kupik [55]

Answer:

k=-2

Step-by-step explanation:

Using substitution to find what you're missing, (in this case k) is when you plug each letter into the other equation:

-4k+3=3k+17

So now solve for k:

subtract 3 from both sides...

-4k=3k+14

subtract 3k from both sides to combine with -4k...

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divide -7 from both sides...

k=-2

3 0
2 years ago
Complete the tables of values.
zlopas [31]

<u>Answer with Step-by-step explanation:</u>

We are given two tables and we are to complete the missing values.

For table one, we are to substitute the given values of x in the term 4^{-x}:

when x = 0, 4^{-0} = 1

when x = 2, 4^{-2} = \frac{1}{16}

when x = 4, 4^{-4} = \frac{1}{256}

For table two, we are to substitute the given values of x in the term (\frac{2}{3} )^x:

when x = 0, (\frac{2}{3} )^0 = 1

when x = 2, (\frac{2}{3} )^2 = \frac{4}{9}

when x = 4, (\frac{2}{3} )^4 = \frac{16}{81}

6 0
4 years ago
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