What is the exponent of 36

Consider the probability that at least 88 out of 158 software users will not call technical support. Assume the probability that

Nookie1986 [14]

Answer:

$E(X) = 158*0.57 =90.06$

And the standard deviation for the random variable is given by:

$\sigma= \sqrt{158*0.57*(1-0.57)} = 6.223$

And the distribution for the approximation is given by:

$X \sim N (\mu = 90.06, \sigma = 6.223)$

We can use the z score formula given by:

$z = \frac{x -\mu}{\sigma}$

And using the complement rule we got:

$P(X \geq 88) = 1-P(X$

And using the standard normal table we got:

$P(X \geq 88) = 1-P(X$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Bin (n = 158, p =0.57)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

We want this probability:

$P(X\geq 88)$

Normal approximation

We need to check if we can use the normal approximation , the conditions are:

$np =158*0.57 = 90.06>10$

$n(1-p) = 158*(1-0.57) = 67.94>10$

Since we satisfy both conditions the normal approximation makes sense

The expected value is given by this formula:

$E(X) = 158*0.57 =90.06$

And the standard deviation for the random variable is given by:

$\sigma= \sqrt{158*0.57*(1-0.57)} = 6.223$

And the distribution for the approximation is given by:

$X \sim N (\mu = 90.06, \sigma = 6.223)$

We can use the z score formula given by:

$z = \frac{x -\mu}{\sigma}$

And using the complement rule we got:

$P(X \geq 88) = 1-P(X$

And using the standard normal table we got:

$P(X \geq 88) = 1-P(X$

4 0

3 years ago

The table shows some of Mr. Puhas's household expenses for the month of February. Mr. Puhas has 500 set aside for utilities. Use

klasskru [66]

Money left = money saved - cost of utilities.

Money left = 500 - 319.45

Money left = 180.55

8 0

2 years ago

In ΔTUV, the measure of ∠V=90°, the measure of ∠T=55°, and VT = 56 feet. Find the length of TU to the nearest tenth of a foot.

HACTEHA [7]

Answer:

97.6

Step-by-step explanation:

4 0

3 years ago

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Rectangle LMNO is rotated 90° clockwise around the origin to create rectangle L'M'N'O'. Which statement would best describe the

mel-nik [20]

Answer:

Segment LL' and segment OO' are congruent (same length) and parallel (same inclination).

hope this helps! :)

Explanation:

The transformation described by the rule (x, y) → (x + 2, y + 2) is a translation two units to the right and two units up.

That means that, to create rectangle L'M'N'O', every point of the reactangle LMNO is translated the same amount in the same direction; thus, this is a rigid transformation where angles, lengths, size, shape, and orientation are kept.

Then a segment drawn from point L to L' will have the same length and the same orientation (inclination) of a segment drawn from the point O to O'. Thus, these two segments are parallel and congruent.

3 0

3 years ago

This this what the tutor gave me

bogdanovich [222]

Answer:

wow thats a lot and looks complicated

4 0

3 years ago

Read 2 more answers