The equation is:
I=100+12J+5T+7S+5H-8M
The given information is that I=197, J=5, T=5, H=3, and M=3, and we’re trying to solve for the amount of shorts (S) he sold.
We can plug in the variables into the equation:
(197)=100+12(5)+5(5)+7S+5(3)-8(3)
After simplification:
197=100+60+25+7S+15-24
We can add/subtract the constants:
197=100+60+25+7S+15-24
We will add/subtract the constants:
197=176+7S
We will subtract 176 from both sides of the equation to cancel it out and isolate 7S:
197-176=176-176+7S
21=7S
We will divide 7 from both sides of the equation to cancel it out and isolate S:
21/7=7S/7
3=S or S=3 with the symmetric property of Equality applied.
Therefore, he sold 3 pairs of shorts
Answer:
The answer is C
Step-by-step explanation:
the rise over run,
, Change in y over Change in x
the rise is -6 and the run is 1 (in other words 
)
Answer:
12.) b = (2S/n) - a
13.) x = 1000 - 20y
Step-by-step explanation:
12.) *goal is to isolate b
S = n/2 (a + b)
S(2/n) = a + b
**multiply both sides by 2/n to get rid of n/2
(2S/n) - a= b
***subtract a from both sides to leave b alone on one side
13.) *goal is to isolate x
0.30x + 6y = 300
0.30x = 300 - 6y
** subtract 6y from both sides
x = (300 - 6y)/ 0.30
*** divide 0.30 from both sides to leave x bu itself
x = 1000 - 20y or -20y +1000
****300 ÷ 0.30 = 1000
-6 ÷ 0.30 = -20
Done!
