Your table of values is so difficult to read that many of us helpers would just skip your post.
<span>x f(x) -6 2.5 -2 2.5 0 2 2 0 3 5 5 2.5 1 0.5</span> could be put into far clearer format as follows:
x f(x)
-- -----
-6 2.5
-2 2.5
and so on. Please fix it.
The "average rate of change" formula is
f(x2) - f(x1)
av r of c = ---------------
x2-x1
so if you go from (-6, 2.5) to (2.5, 10.5), the av r of c would be
10.5 - 2.5 9 18
------------------ = -------- = -----
2.5-(-6) 8.5 17
This may or may not be your final answer. Again, please put your data table into readable form and then find the av r of c over the interval [-2,3].
SCale factor is ML/DC = 6/4 = 3/2
So multiply AD by 3/2 to find the length of JM . The length would be 3*3/2=9/2
Next find the perimeter of JKML. It would be 2(9/2+6)=21
Answer:
10
Step-by-step explanation:
F=kx
Use this formula of Hooke's law
Answer: 305.9m
Area of a Triangle is 1/2 base X height
So (b)(h) = 2.1m X 19m=39.9m (210 cm = 2.1 m)
Now that we have the base which is 39.9m
We do the sides which is 1/2*28*19=266m
Now that we have the sides, we add the base which is 39.9m and the Height which is 266m, then we get our answer: 305.9m
I hope this helped you. Goodluck, and please give me a Branliest if available. Thanks. :)
.78 + 10% = .858 Hope this helps!!
