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Sidana [21]
3 years ago
8

The dot plot shows the number of hours that students spent watching TV. A dot plot titled hours students spend watching T V per

week. The dot plot goes from 3 to 20 and is labeled hours. The data is as follows. 16 dots above 3, 13 dots above 4, 14 dots above 5, 2 dots above 6, 7, 8, 9, and 10, 8 dots above 11, 11 dots above 12 and 13, 3 dots above 14, 15, and 16, 0 dots above 17, 18, and 19, and 1 dot above 20. Select all the statements that are true. A typical student from this group spends more than 10 hours watching television each week. More students watch 3 hours of television than watch more than 3 hours of television. All students watch 20 or fewer hours of television each week. The most common answer for the number of hours that a student watches per week was 3. Some students do not watch any TV during the week.
Mathematics
1 answer:
Grace [21]3 years ago
3 0

Answer:

The answer is , More students watch 3 hours of television than watch more than 3 hours of television.

Step-by-step explanation:

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Carbon-14 is a radioactive isotope that has a half-life of 5,730 years. Approximately how many years will it take for carbon-14
PilotLPTM [1.2K]

Answer:

<em>Carbon-14 will take 19,035 years to decay to 10 percent.</em>

Step-by-step explanation:

<u>Exponential Decay Function</u>

A radioactive half-life refers to the amount of time it takes for half of the original isotope to decay.

An exponential decay can be described by the following formula:

N(t)=N_{0}e^{-\lambda t}

Where:

No  = The quantity of the substance that will decay.

N(t) = The quantity that still remains and has not yet decayed after a time t

\lambda     = The decay constant.

One important parameter related to radioactive decay is the half-life:

\displaystyle t_{1/2}=\frac {\ln(2)}{\lambda }

If we know the value of the half-life, we can calculate the decay constant:

\displaystyle \lambda=\frac {\ln(2)}{ t_{1/2}}

Carbon-14 has a half-life of 5,730 years, thus:

\displaystyle \lambda=\frac {\ln(2)}{ 5,730}

\lambda=0.00012097

The equation of the remaining quantity of Carbon-14 is:

N(t)=N_{0}e^{-0.00012097\cdot t}

We need to calculate the time required for the original amout to reach 10%, thus N(t)=0.10No

0.10N_o=N_{0}e^{-0.00012097\cdot t}

Simplifying:

0.10=e^{-0.00012097\cdot t}

Taking logarithms:

ln 0.10=-0.00012097\cdot t

Solving for t:

\displaystyle t=\frac{log 0.10}{-0.00012097}

t\approx 19,035\ years

Carbon-14 will take 19,035 years to decay to 10 percent.

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Answer:

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Step-by-step explanation:

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