The Bernoulli distribution is a distribution whose random variable can only take 0 or 1
- The value of E(x2) is p
- The value of V(x) is p(1 - p)
- The value of E(x79) is p
<h3>How to compute E(x2)</h3>
The distribution is given as:
p(0) = 1 - p
p(1) = p
The expected value of x2, E(x2) is calculated as:

So, we have:

Evaluate the exponents

Multiply

Add

Hence, the value of E(x2) is p
<h3>How to compute V(x)</h3>
This is calculated as:

Start by calculating E(x) using:

So, we have:


Recall that:

So, we have:

Factor out p

Hence, the value of V(x) is p(1 - p)
<h3>How to compute E(x79)</h3>
The expected value of x79, E(x79) is calculated as:

So, we have:

Evaluate the exponents

Multiply

Add

Hence, the value of E(x79) is p
Read more about probability distribution at:
brainly.com/question/15246027
Y=8,4,2,-2 linear and in that order
-x - 5 = -11
add 5 to both sides
-x - 5 + 5 = -11 + 5
-x = -6
x = 6
Answer:
Hence the value for the mean is 80 and the standard deviation for the original sample is 8.
Step-by-step explanation:
Mean = 83-3 = 80.
Here the standard deviation didn't change = 8.
Answer:
-2 2/3
Step-by-step explanation:
I am pretty sure