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dedylja [7]
3 years ago
13

What is the area formula for trapezoid

Mathematics
1 answer:
asambeis [7]3 years ago
5 0

Answer:A

=

a

+

b

2

h

Step-by-step explanation:

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Round 314550 to 1 significant figure​
Sauron [17]
300000 all you had to do was round the number down after the 1 significant figure

you round down with
1,2,3,4

and round up with
5,6,7,8,9

so if it asked for 78453
to 2 significant figures you count the numbers and round after that
so 78|453 and since 4 is the next number and it is less that 5 we round down which means it becomes 78000 with is lower than 78453

but if we had 0.0247
and it asked for this number to 2 significant figures all you need to do is count the SIGNIFICANT figures significant means anything with value so that is 1,2,3,4,5,6,7,8,9,10.... 0 has no value therefore we ignore 0 and start counting at the first figure larger than 0
if we go back to 0.0247 that would be the 2 so 2 significant figure of 0.0247 would equal
0.024|7
7 is larger than 5 so we round up to
0.025
tadaa i hope that helped
8 0
3 years ago
Read 2 more answers
Explain why Rolle's Theorem does not apply to the function even though there exist a and b such that f(a)
Anna35 [415]

Rolle's Theorem does not apply to the function because there are points on the interval (a,b) where f is not differentiable.

Given the function is f(x)=\sqrt{(2-x^{\frac{2}{3}})^{3}}  and the Rolle's Theorem does not apply to the function.

Rolle's theorem is used to determine if a function is continuous and also differentiable.

The condition for Rolle's theorem to be true as:

  • f(a)=f(b)
  • f(x) must be continuous in [a,b].
  • f(x) must be differentiable in (a,b).

To apply the Rolle’s Theorem we need to have function that is differentiable on the given open interval.

If we look closely at the given function we can see that the first derivative of the given function is:

\begin{aligned}f(x)&=\sqrt{(2-x^{\frac{2}{3}})^3}\\ f(x)&=(2-x^{\frac{2}{3}})^{\frac{3}{2}}\\ f'(x)&=\frac{3}{2}(2-x^{\frac{2}{3}})^{\frac{1}{2}}\cdot \frac{2}{3}\cdot (-x)^{\frac{1}{3}}\\ f'(x)&=\frac{-\sqrt{2-x^{\frac{2}{3}}}}{\sqrt[3]{x}}\end

From this point of view we can see that the given function is not defined for x=0.

Hence, all the assumptions are not satisfied we can reach a conclusion that we cannot apply the Rolle's Theorem.

Learn more about Rolle's Theorem from here brainly.com/question/12279222

#SPJ4

8 0
2 years ago
What type of function would you use to model the height a bull thrown in the air travel over a period of time ?
tia_tia [17]
Airplane I DONT KNOW ANYTHING LOL
3 0
3 years ago
The amount of money in a saving account increase from $250 to $270 what is the precent increase of the money in the savings acco
saveliy_v [14]

Answer:

8%

Step-by-step explanation:

percent increase = [ (difference between initial value and final value) ÷ initial value] x 100

⇒ percent increase = [ (270 - 250) ÷ 250] x 100 = 8%

7 0
3 years ago
Read 2 more answers
I need help with this so could you give me the answers with an explanation if you can.​
Katarina [22]

Answer:

2.44745763 \times  {10}^{6}

Step-by-step explanation:

R =  \frac{ {x}^{2} }{y}  \\  \\  =  \frac{ {(3.8 \times  {10}^{5}) }^{2} }{5.9 \times  {10}^{4} }  \\  \\  =  \frac{14.44 \times  {10}^{10} }{5.9 \times  {10}^{4} }  \\  \\  = 2.44745763 \times  {10}^{10 - 4}  \\ = 2.44745763 \times  {10}^{6}

4 0
3 years ago
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