Question

Please I really need help on this thank you.

Answer 1

(a)

slope of f(x):

We can select any two points to find slope

(0,-3) and (1,0)

now, we can use slope formula

$m=\frac{y_2-y_1}{x_2-x_1}$

now, we can plug values

$m=\frac{0+3}{1-0}$

$m=3$

slope of g(x):

$g(x)=4x-5$

we can compare it with slope intercept form of line

$g(x)=mx+b$

we get

$m=4$

so, we can see that slope of f(x) is 3 while slope of g(x) is 4

so, slope of g(x) is greater than slope of f(x)

(b)

y-intercept of f(x):

we know that y-intercept is value of y when x=0

we are given point (0,-3)

so, y-intercept is -3

y-intercept of g(x):

we know that y-intercept is value of y when x=0

so, we can plug x=0 and find y

$g(0)=4*0-5$

$y=-5$

so, y-intercept is -5

Since, -3 is greater than -5

Hence , y-intercept of f(x) has greater value.........Answer