Hello from MrBillDoesMath!
Answer:
27 x^2 sqrt(x^3) sin(x^3) - 9/2 sqrt(x^1/2) sin(x^1/2)*x^(-1/2)
Discussion:
Let f(t) - 9 sqrt(t) sin(t), then
y' = f(x^3) * d(x^3)/dx - f(sqrt(x)) * d(x^1/2)/dx
= (9 sqrt(x^3)sin(x^3)) * 3x^2 - (9 sqrt(x^1/2)sin(x^1/2)) * (1/2) x^-(1/2)
= 27 x^2 sqrt(x^3) sin(x^3) - 9/2 sqrt(x^1/2) sin(x^1/2)*x^(-1/2)
Hope I didn't make a "bozo" error differentiating things!
Thank you,
MrB
Square units are the units of measuring area. Therefore, this question asks for the area of the room.
The room has the shape of a rectangle with:
length = 13 units and width = 9 units
The are of the rectangle can be calculated using the following rule:
area of rectangle = length * width
area of the room = 13 * 9 = 117 square units
Answer: 7.62
Step-by-step explanation:
A .
- If the number after the decimal is 5+ you round up .. if its 4 and below you round down
