Answer:
I believe it is X * 2 + 5 = Jim's total
Step-by-step explanation:
X is the amount of hours Kelly reads and multiplying X by 2 is how you find Tim's total. Then to find Jim's total you add 5 because that's how many more hours he reads than Tim.
Answer:
it depends what level math you are in, there are two answers, if it asks for two answers then the two answers are 2 and -2 if it only asks for one answer then put 2
Step-by-step explanation:
Answer:
around 1.36
Step-by-step explanation:
Important: 35x2 12x − 36 is not an equation; to obtain an equation, you must set <span>35x2 12x − 36 = to 0:
</span><span>35x^2 + 12x − 36 = 0. Also, "the square of x" must be represented by "x^2," and you must insert either the + or the - sign in front of the term 12x.
I am assuming that you meant </span>35x^2 + 12x − 36 = 0.
If that is indeed the case, then a = 35, b = 12 and c = -36
and the discriminant is b^2 - 4ac, or (12)^2 - 4(35)(-36) = 5184.
Since the discriminant is positive, this equation has 2 real, unequal solutions. They are
-12 plus or minus sqrt(5184)
x = -----------------------------------------
2(35)
Answer: 35 inches.
Step-by-step explanation:
We know that:
hypotenuse = 5*y in
cathetus 1 = (x + 8) in
cathetus 2 = (x + 3) in
The perimeter of the triangle is 76 inches, then:
5*y + (x + 8) + (x + 3) = 76
5*y + 2*x + 13 = 76
We also know that the length of the hypotenuse minus the length of the shorter leg is 17 in.
The shorter leg is x + 3, then:
5*y - (x + 3) = 17
Then we have the equations:
5*y + 2*x + 11 = 76
5*y - (x + 3) = 17
With only these two we can solve the system, first we need to isolate one of the variables in one of the equations, i will isolate x in the second equation.
x = 5*y - 3 - 17 = 5*y - 20
x = 5*y - 20
Now we can replace this in the other equation, we get:
5*y + 2*x + 11 = 76
5*y + 2*(5*y - 20) + 11 = 76
15*y - 40 + 13 = 76
15*y - 29 = 76
15*y = 76 + 29 = 105
and remember that the hypotenuse is equal to 5*y, then we want to get:
3*(5*y) = 105
5*y = 105/3 = 35
5*y = 35
Then te length of the hypotenuse is 35 inches.