2 years ago

If sinA÷2 =4÷2 find the value of cosA (not by pythagoras theorem)

Mathematics

1 answer:

Grace [21]2 years ago

6 0

Answer:

Step-by-step explanation:

Sin A ÷ 2 = 2

Sin A = 2×2

Sin A = 4

Cos A = sqrt (1 - Sin ^2 A) = sqrt(1 - 4^2)

Cos A = sqrt(1-16) = sqrt (-15) = sqrt(15i^2)

Cos A = i sqrt(15)

You might be interested in

Help please I need help

serg [7]

He could use the mode of 89.

6 0

3 years ago

The product of 12 and k is 84.

Vesnalui [34]

Answer:

to solve this we do the oppisite of multiplication which is division

so 84 divided by 12 = 7 so that means that our mysterious k = 7

so reprhase the sentence so '' The product of 12 and 7 is 84

hope this helps:)

Step-by-step explanation

8 0

3 years ago

Read 2 more answers

What three that are equivalent to 4:3.

stich3 [128]

Three that are equivalent are 12:9 8:6 28:21

5 0

2 years ago

I will give brainliest <br> Find n. <br> 35n/35 = 700/35

adoni [48]

Answer:

Step-by-step explanation:

$\frac{35n}{35} =\frac{700}{35} \\$

multiply both sides by 35

$35*\frac{35n}{35} = 700 * 35\\35n = 700$

divide both sides by 35

$n = 20$

6 0

3 years ago

Read 2 more answers

you scored 72% on the Unit 1 exam and then 90% on the unit 2 exam. what was your percentage acorr increase

iVinArrow [24]

The difference between 90% and 72% is 18%

6 0

3 years ago

If sinA÷2 =4÷2 find the value of cosA (not by pythagoras theorem)​

If sinA÷2 =4÷2 find the value of cosA (not by pythagoras theorem)