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3 years ago

What is the algebra expression for 4 minus the sum of a number and 6

Mathematics

1 answer:

Westkost [7]3 years ago

8 0

Answer:

(x+6)-4

Step-by-step explanation:

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#1- Jennifer made a box plot to summarize this data. 124, 118, 129, 139, 133, 129, 142, 135, 122, 137. What is the median, the l

svp [43]

Answer:

B or

Lower quartile: 124

Median: 131

Upper quartile: 137

Step-by-step explanation:

To find the median first make the data in order from greatest to least:

118,122,124,129,129,133,135,137,139,142

Then find the middle 2 numbers which are 129 and 133

129+133=262 (divide by 2 to find average) so

median= 262/2=131

To find the Lower quartile find the number in the middle of the first 5 numbers which is 124

To find the Upper quartile find the number in the middle of the second 5 numbers which is 137 so

B or

Lower quartile: 124

Median: 131

Upper quartile: 137

8 0

3 years ago

TV and YW are parallel lines.

Lemur [1.5K]

Answer: C, WXZ and WXU are adjacent angles.

Step-by-step explanation:

A is incorrect because TUX and VUS are vertical angles.

B is incorrect because YXZ and TUX have no relationship.

C is correct because WXZ and WXU are supplementary angles, thus adjacent.

D is inccorect because VUX and TUS are vertical angles.

6 0

3 years ago

Andre brought a new bag of cat food. The next day, he opened it to feed his cat. The graph shows how many ounces were left in th

GalinKa [24]

39 days so you would put 39 days till the bag was empty

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3 years ago

Y=arccos(1/x)<br><br> Please help me do them all! I don’t know derivatives :(

Stells [14]

Answer:

$f(x) = {sec}^{ - 1} x \\ let \: y = {sec}^{ - 1} x \rightarrow \: x = sec \: y\\ \frac{dx}{dx} = \frac{d(sec \: y)}{dx} \\ 1 = \frac{d(sec \: y)}{dx} \times \frac{dy}{dy} \\ 1 = \frac{d(sec \: y)}{dy} \times \frac{dy}{dx} \\1 = tan \: y.sec \: y. \frac{dy}{dx} \\ \frac{dy}{dx} = \frac{1}{tan \: y.sec \: y} \\ \frac{dy}{dx} = \frac{1}{ \sqrt{( {sec}^{2} \: y - 1}) .sec \: y} \\ \frac{dy}{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} } \\ \therefore \frac{d( {sec}^{ - 1}x) }{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} } \\ \frac{d( {sec}^{ - 1}5x) }{dx} = \frac{1}{ |5x | \sqrt{25 {x }^{2} - 1} }\\\\y=arccos(\frac{1}{x})\Rightarrow cosy=\frac{1}{x}\\x=secy\Rightarrow y=arcsecx\\\therefore \frac{d( {sec}^{ - 1}x) }{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} }$

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3 years ago

Yolonda withdrew 60 dollars from her checking account.Write a signed number to represent this change in her account.

JulsSmile [24]

Answer:

$ 60.00

Step-by-step explanation:

8 0

3 years ago