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2 years ago

ASAP PLZ IM TIMED I WILL GIVE BRAINLIEST

Mathematics

1 answer:

katrin [286]2 years ago

3 0

Step-by-step explanation:

${ \huge{ \red{ \bf( \frac{3}{4} ) {}^{3} }}}$

${ \huge{ \blue{ \bf{( \frac{3 \times 3 \times 3}{4 \times 4 \times 4} )}}}}$

${ \large{ \pink{ \boxed{ \tt{ \bigg( \frac{27}{64} { \bigg)}}}ans.}}}$

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How do the mathematical domain and reasonable domain compare

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2 years ago

Simplify 9 log9 (7) is the answer 7

Aleks04 [339]

$log_ab=c\ \ \ \Leftrightarrow\ \ \ a^c=b\\\\log_97=x\ \ \ \Leftrightarrow\ \ \ 9^x=7\\\\9^x=7\ \ \ (and \ \ \ x=log_97)\ \ \ \Rightarrow\ \ \ 9^{\big{log_97}}=7$

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3 years ago

Find the leading coefficient and write the factored form of the function of least degree for the polynomial in the graph below.

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2 years ago

The perimeter of this triangle is 25 units. An angle bisector divides one side of the triangle into lengths of 2 and 3. Find the

grin007 [14]

Answer:

8 and 12

Step-by-step explanation:

Sides on one side of the angle bisector are proportional to those on the other side. In the attached figure, that means

AC/AB = CD/BD = 2/3

The perimeter is the sum of the side lengths, so is ...

25 = AB + BC + AC

25 = AB + 5 + (2/3)AB . . . . . . substituting AC = 2/3·AB. BC = 2+3 = 5.

20 = 5/3·AB

12 = AB

AC = 2/3·12 = 8

_____

<em>Alternate solution</em>

The sum of ratio units is 2+3 = 5, so each one must stand for 25/5 = 5 units of length.

That is, the total of lengths on one side of the angle bisector (AC+CD) is 2·5 = 10 units, and the total of lengths on the other side (AB+BD) is 3·5 = 15 units. Since 2 of the 10 units are in the segment being divided (CD), the other 8 must be in that side of the triangle (AC).

Likewise, 3 of the 15 units are in the segment being divided (BD), so the other 12 units are in that side of the triangle (AB).

The remaining sides of the triangle are AB=12 and AC=8.

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3 years ago

Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your

Veronika [31]

The expression of integral as a limit of Riemann sums of given integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ is 4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$ from i=1 to i=n.

Given an integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ .

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

$\int\limits^b_a {f(x)} \, dx$ = $\lim_{n \to \infty}$ ∑f(a+iΔx)Δx ,here Δx=(b-a)/n

$\int\limits^5_1 {x/(2+x^{3}) } \, dx$ =f(x)= $x/2+x^{3}$

⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

f(1+4i/n)= $[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}$

$\lim_{n \to \infty}$ ∑f(a+iΔx)Δx=

$\lim_{n \to \infty}$ ∑ $n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n$

=4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$

Hence the expression of integral as a limit of Riemann sums of given integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ is 4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$ from i=1 to i=n.

Learn more about integral at brainly.com/question/27419605

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1 year ago

ASAP PLZ IM TIMED I WILL GIVE BRAINLIEST ​

ASAP PLZ IM TIMED I WILL GIVE BRAINLIEST