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3 years ago

Work out the balance for £3000 invested for 3 years at 5% per annum

1 answer:

6 0

It depends in the type on interest

Simple Interest
PxRxT
£3000 x 0.05 x 3 = £450
£3000 + £450 = £3450

Compound Interest
Px(1+R)^T
£3000 x (1 + 0.05)³ = £3472.875 = £3472.88

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Butter and flour are mixed in the ratio 2 : 3.Chris has 640 grams of butter and 880 grams of flour.How much more flour does he n

VMariaS [17]

he need 1000 grams of all

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3 years ago

Please help!! I NEED IT VERY BADLY

I am Lyosha [343]

Answer:

3/4

Step-by-step explanation:

tan A =opposite/adjacent = 6/8 =3/4

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3 years ago

A statue stands on a 625 m2 base. An artist creates a replica using a ratio of 1:10 What is the area of the replica's base?

DedPeter [7]

The new area of the given replica's base is; 6250 m²

<h3>What is the required area?</h3>

We are given;

Area of base of statue = 625 m²

Now, an artist wants to create a replica of the base of statue but in the ratio 1:10.

This means that the area will increase by a factor of 10 as 1 sq.unit of the old area will represent 10 sq. units in the new one.

Thus, new area = 625 * 10

New area of statue = 6250 m²

Read more about new area at; brainly.com/question/26858128

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2 years ago

Mauricio divided two identical rectangles into equal parts. He colored one part of each rectangle. What is true about the areas

Ivenika [448]

Answer:

Areas of the colored parts are equal

Step-by-step explanation:

Given Mauricio divided two identical rectangles into equal parts.

Now given Mauricio colored one part of each rectangle. we have to tell about the true statement of colored parts.

Two identical rectangles means the rectangle having equal areas. He divides these two into equal parts and shaded one of each part

Let area of rectangle is x $unit^{2}$

∴ Colored part area = $\frac{1}{2}xunit^{2}$ → (1)

Similarly, other rectangle area identical to above rectangle is x $unit^{2}$

∴ Colored part area = $\frac{1}{2}xunit^{2}$ → (2)

From above eq (1) and (2), we get

Areas of the colored parts are equal which is equals to $\frac{1}{2}xunit^{2}$

4 0

3 years ago

you are shopping for disposable cameras to hand out at a party. the daytime cameras costs 2.75 dollars and the flash camera cost

LenKa [72]

The solutions that involve whole numbers of cameras are (7, 13), (8, 12), (9, 11), (10, 10), (11, 9), (12, 8) and (13, 7)

<h3>Write and solve a compound inequality for this solution. </h3>

The given parameters are:

Daytime cameras = $2.75
Flash camera = $4.25
Number of cameras = 20 cameras
Amount spent = Between $65 and $75

Represent the daytime camera with x and the flash camera with y.

So, we have:

x + y = 20

65 <=2.75x + 4.25y <= 75

Make y the subject in x + y = 20

y = 20 - x

Substitute y = 20 - x in 65 <=2.75x + 4.25y <= 75

65 <=2.75x + 4.25(20 - x) <= 75

Expand

65 <=2.75x + 85 - 4.25x <= 75

This gives

65 <=-1.5x+ 85 <= 75

Subtract 85 from the inequality

-20 <=-1.5x <= -10

Split the inequality

-1.5x >= -20 and -1.5x <= -10

Divide by -1.5

x <= 13.33 and x >= 6.67

Combine the inequality

6.67 <= x <= 13.33

<h3>List all of the solutions that involve whole numbers of cameras.</h3>

In (a), we have:

6.67 <= x <= 13.33

This means that:

x = 7, 8, 9, 10, 11, 12, 13

Recall that:

y = 20 - x

So, we have:

y = 13, 12, 11, 10, 9, 8, 7

So, the solutions that involve whole numbers of cameras are (7, 13), (8, 12), (9, 11), (10, 10), (11, 9), (12, 8) and (13, 7)