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Fiesta28 [93]
3 years ago
10

Pls help I'm in the test rn

Mathematics
1 answer:
monitta3 years ago
7 0

Answer: 2005

Step-by-step explanation: Because, each year it goes down 4, but 50-4=46 not 44. I hope this helped!

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The value of coin A is twice the value of coin B. Together, the total value of the two coins is $27.00 What is the value of each
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27÷2=$13.50

Step-by-step explanation:

Easy

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F(x)=x^2+2x-1 <br>find f(-3)​
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2

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Solve for X. x-9+2wx=y
iragen [17]

Answer:

x=(y+9)/(1+2w)

Step-by-step explanation:

x-9+2wx=y

We make x the subject

x+2wx=y+9

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3 years ago
Let alpha and beta be conjugate complex numbers such that frac{\alpha}{\beta^2} is a real number and alpha - \beta| = 2 \sqrt{3}
miskamm [114]

Answer:

-3+i\sqrt{3} , 1+\sqrt{3}

Step-by-step explanation:

Given that alpha and beta be conjugate complex numbers

such that frac{\alpha}{\beta^2} is a real number and alpha - \beta| = 2 \sqrt{3}.

Let

\alpha = x+iy\\\beta = x-iy

since they are conjugates

\alpha-\beta = x+iy-(x-iy)\\= 2iy= 2i\sqrt{3} \\y =\sqrt{3}

\frac{\alpha}{\beta^2} }\\=\frac{x+i\sqrt{3} }{(x-i\sqrt{3})^2} \\=\frac{x+i\sqrt{3}}{x^2-3-2i\sqrt{3}} \\=\frac{x+i\sqrt{3}((x^2-3+2i\sqrt{3}) }{(x^2-3-2i\sqrt{3)}(x^2-3-2i\sqrt{3})}

Imaginary part of the above =0

i.e. \sqrt{3} (x^2-3)+2x\sqrt{3} =0\\x^2+2x-3=0\\(x+3)(x-1) =0\\x=-3,1

So the value of alpha = -3+i\sqrt{3} , 1+\sqrt{3}

3 0
3 years ago
A national trivia tournament starts with 262,144 teams. With each round, there are half as many teams as before. The number of t
nirvana33 [79]

Answer:

D.) The mathematical range is all real numbers greater than 0. The reasonable range is all whole numbers greater than 0 and less than or equal to 262,144.

Step-by-step explanation:

I don't even know, but yeah.

5 0
3 years ago
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