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3 years ago

Choose a random number between 1 and 25. What is the probability that it is an even number

Mathematics

1 answer:

CaHeK987 [17]3 years ago

3 0

Answer:

6/25

Step-by-step explanation:

its a probability out of all the odd numbers such as 1,3,5,7,9,11,13,15,17,19,21,23,25

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Which of these is equivalent to 3π/5 rad ? A) 108° B) 150° C) 216° D) 300°

Reptile [31]

To convert from radians to degrees multiply by 180 / π, So:-

3 π / 5 = 180 * 3 * π / 5π

= 540 / 5

= 108 degrees answer

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3 years ago

Which of the following is not a typical characteristic of a linear programming problem?

adell [148]

The answer is c. The problem can be solved graphically

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3 years ago

You spent 904 dollars including tax to computer. Tax is 13% Find out the price of the computer.

vazorg [7]

The answer to your question is 915.75 I think

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2 years ago

PLZ ANSWER QUESTION IN PICTURE

viktelen [127]

Answer:

X-int = -5 and y-int = 6

Step-by-step explanation:

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1.2x= -6

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3 years ago

A certain college graduate borrows 7864 dollars to buy a car. The lender charges interest at an annual rate of 13%. Assuming tha

White raven [17]

Answer:

Therefore rate of payment = $ 3145.72

Therefore the rate of interest = =$1573.17

Step-by-step explanation:

Consider A represent the balance at time t.

A(0)=$ 7864.

r=13 % =0.13

Rate payment = $k

The balance rate increases by interest (product of interest rate and current balance) and payment rate.

$\frac{dB}{dt} = rB-k$

$\Rightarrow \frac{dB}{dt} - rB=-k$ .......(1)

To solve the equation ,we have to find out the integrating factor.

Here p(t)= the coefficient of B =-r

The integrating factor $=e^{\int p(t) dt$

$=e^{\int (-r)dt$

$=e^{-rt}$

Multiplying the integrating factor the both sides of equation (1)

$e^{-rt}\frac{dB}{dt} -e^{-rt}rB=-ke^{-rt}$

$\Rightarrow e^{-rt}dB - e^{-rt}rBdt=-ke^{-rt}dt$

Integrating both sides

$\Rightarrow \int e^{-rt}dB -\int e^{-rt}rBdt=\int-ke^{-rt}dt$

$\Rightarrow e^{-rt}B=\frac{-ke^{-rt}}{-r} +C$ [ where C arbitrary constant]

$\Rightarrow B(t)=\frac{k}{r} +Ce^{rt}$

Initial condition B=7864 when t =0

$\therefore 7864= \frac{k}{r} - Ce^0$

$\Rightarrow C= \frac{k}{r} -7864$

Then the general solution is

$B(t)=\frac{k}{r}-( \frac{k}{r}-7864)e^{rt}$

To determine the payment rate, we have to put the value of B(3), r and t in the general solution.

Here B(3)=0, r=0.13 and t=3

$B(3)=0=\frac{k}{0.13}-( \frac{k}{0.13}-7864)e^{0.13\times 3}$

$\Rightarrow- 0.48\frac{k}{0.13} +11614.98=0$

⇒k≈3145.72

Therefore rate of payment = $ 3145.72

Therefore the rate of interest = ${(3145.72×3)-7864}

=$1573.17

4 0

3 years ago