3 years ago

Choose a random number between 1 and 25. What is the probability that it is an even number

Mathematics

1 answer:

CaHeK987 [17]3 years ago

3 0

Answer:

6/25

Step-by-step explanation:

its a probability out of all the odd numbers such as 1,3,5,7,9,11,13,15,17,19,21,23,25

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Carrie had 3 1/2 candy bars that she wanted to divide between herself and her friend harry how many candy bars each Girl get?

expeople1 [14]

Answer:

1 3/4

Step-by-step explanation:

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3 years ago

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ANTONII [103]

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3 years ago

Using hundredths grids for subtracting what is the answer to 1.65-0.98?

mote1985 [20]

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4 years ago

D is between C and E, CD = x 2 , CE = 32-2x, and DE = 12x. Find CD, DE, and CE.

Gemiola [76]

Answer:

CD = 4
DE = 24
CE = 28

Step-by-step explanation:

The segment addition theorem tells you ...

CD +DE = CE

x^2 +12x = 32 -2x

Subtract the right side to put this in standard form.

x^2 +14x -32 = 0

(x +16)(x -2) = 0

x = -16 or 2

In order for DE to have a positive length, we must have x > 0. So ...

CD = x^2 = 2^2 = 4

DE = 12x = 12(2) = 24

CE = 32 -2x = 32 -2(2) = 28

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3 years ago

X (dy/dx) = (y-1/y+1)-y

notsponge [240]

F' $( \frac{y-1}{y+1})-y$ =
f' $( \frac{y-1}{y+1})$ -f'(y) [/tex]=
$\frac{f'(y-1)(y+1)-f'(y+1)(y-1)}{(y+1)^2} -1$ =
$\frac{(f'(y)-f'(1))(y+1)-(f'(y)+f'(1))(y-1)}{(y+1)^2} -1$ =
$\frac{(1-0)(y+1)-(1-0)(y-1)}{(y+1)^2} -1$ =
$\frac{(1)(y+1)-(1)(y-1)}{(y+1)^2} -1$ =
$\frac{(y+1)-(y-1)}{(y+1)^2} -1$ =
$\frac{y+1-y+1}{(y+1)^2} -1$ =
$\frac{2}{(y+1)^2} -1$

8 0

3 years ago