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Answer:
a) ∆RLG ~ ∆NCP; SF: 3/2 (smaller to larger)
b) no; different angles
Step-by-step explanation:
a) The triangles will be similar if their angles are congruent. The scale factor will be the ratio of any side to its corresponding side.
The third angle in ∆RLG is 180° -79° -67° = 34°. So, the two angles 34° and 67° in ∆RLG match the corresponding angles in ∆NCP. The triangles are similar by the AA postulate.
Working clockwise around each figure, the sequence of angles from lower left is 34°, 79°, 67°. So, we can write the similarity statement by naming the vertices in the same order: ∆RLG ~ ∆NCP.
The scale factor relating the second triangle to the first is ...
NC/RL = 45/30 = 3/2
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b) In order for the angles of one triangle to be congruent to the angles of the other triangle, at least one member of a list of two of the angles must match for the two triangles. Neither of the numbers 57°, 85° match either of the numbers 38°, 54°, so we know the two triangles have different angle measures. They cannot be similar.
1. Take out the constants
-(2 x 3 x 4 x 2)xxyy^3
2. Simplify 2 x 3 x 4 x 2 to 48
-48xxyy^3
3. Use Product Rule: x^ax^b = x^a+b
-48x^1+1y^1+3
4. Simplify 1 + 1 to 2
-48x^2y^1+3
5. Simplify 1 + 3 to 4
-48x^2y^4
Not exactly sure but I think it's false hope this helps
