Find the sum of the arithmetic series: 10 + 4 + (-2) + ... + (-50)
1 answer:
You might be interested in
<u>Answer:</u>
<u>Step-by-step explanation:</u>
32a^3 + 12a^2
To factorize this, start by taking the common variable out. As we have two powers for the same variable a, we can take the smaller power of a as a common to get like shown below:
32a^3 + 12a^2
a^2 (32a + 12)
Now when you have taken the variable as a common, try and take out a common number from the coefficient of a as well:
a^2 (32a + 12)
4a^2 (8a + 3)
So, the fully factored form of 32a^3 + 12a^2 is 4a^2 (8a + 3).