Note that c is the hypotenuse of the blue triangle, and that the Pyth. Thm. states that (length of one leg)^2 + (length of the other leg)^2 = (hyp)^2.
Therefore, (hyp)^2 = c^2 = [2sqrt(x^2+3x)]^2 + 3^2, or
= 4(x^2+3x) + 9, or
= 4x^2 + 12x + 9 = (2x+3)^2
Taking the sqrt of both sides, c = plus or minus (2x+3). Eliminate -(2x+3) because the middle term of the square of this would be negative, in conflict with the given +12x.
c=2x+3 is the correct answer.
There are the combinations that result in a total less than 7 and at least one die showing a 3:
[3, 3] [3,2] [2,1] [1,3] [2,3]
The probability of each of these is 1/6 * 1/6 = 1/36
There is a little ambiguity here about whether or not we should count [3,3] as the problem says "and one die shows a 3." Does this mean that only one die shows a 3 or at least one die shows a 3? Assuming the latter, the total probability is the sum of the individual probabilities:
1/36 + 1/36 + 1/36 + 1/36 + 1/36 = 5/36
Therefore, the required probability is: 5/36
Answer:
-2.5 = x
Step-by-step explanation:
-10 = 4x
the equation between 4 and x is multiplication
as our goal is to move the x on its separate side, we should divide each side by 4 to get rid of the bond between the 4 and the x
Therefore,
-10 = 4x
-10/4 = x
Simplify into decimal if needed
-2.5 = x
Hope that helped!!! k
Answer:
2 cases of soya bean milk will have the same volume as 1 case of fruit juice.
Step-by-step explanation:
Let the case of soya beans drink be x and let the case of fruit juice be y
We are told that the room can store either 10 cases of soya beans drink and 8 cases of fruit juice or 4 cases of soybeans drink and 11 cases of fruit juice.
This means that;
10x + 8y = 4x + 11y
Rearranging, we have;
10x - 4x = 11y - 8y
6x = 3y
Thus;
y = 6x/3
y = 2x
This means that 2 cases of soya bean milk will have the same volume as 1 case of fruit juice.
-5x•(2x^2+x+3) is the answer
