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3 years ago

7

Write an integer to match the following descriptions. a. A debit of $40 b. A deposit of $225 c. 14,000 feet above sea level d. A

temperature increase of 40°F e. A withdrawal of $225 f. 14,000 feet below sea level

2 answers:

Hatshy [7]3 years ago

8 0

Hi I’m trying to help but I can’t find this

vaieri [72.5K]3 years ago

4 0

Glee

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Use the graph of the line shown.

Paladinen [302]

Answer:

that is the answer to letter A y=3/10+3

That is the answer to letter B 3

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3 years ago

The red graph represents P(x) = x5. Which polynomial function could represent the transformed curve shown in blue?

Dmitry [639]

Answer: the answer I got was p(x)=2x5-4

Step-by-step explanation:

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4 years ago

Determine which of the following sets of three points constitute the vertices of a right triangle: (a) 3 + 5i,2 +2i,5i; (b)2i,3

Illusion [34]

Answer:

Option (c) is correct

Step-by-step explanation:

Case (a)

A = 3 + 5i = (3, 5)

B = 2 + 2i = (2, 2)

C = 5i = (0, 5)

Use the distance formula to find the distance between two points

$AB = \sqrt{(2-3)^{2}+(2-5)^{2}}=\sqrt{10}$

$BC = \sqrt{(0-2)^{2}+(5-2)^{2}}=\sqrt{13}$

$CA = \sqrt{(0-3)^{2}+(5-5)^{2}}=\sqrt{9}$

For the triangle to be right angles triangle

$BC^{2}=AB^{2}+CA^{2}$

Here, it is not valid, so these are not the points of a right angled triangle.

Case (b)

A = 2i = (0, 2)

B = 3 + 5i = (3, 5)

C = 4 + i = (4, 1)

Use the distance formula to find the distance between two points

$AB = \sqrt{(3-0)^{2}+(5-2)^{2}}=\sqrt{18}$

$BC = \sqrt{(4-3)^{2}+(1-5)^{2}}=\sqrt{17}$

$CA = \sqrt{(4-0)^{2}+(1-2)^{2}}=\sqrt{17}$

For the triangle to be right angles triangle

$AB^{2}=BC^{2}+CA^{2}$

Here, it is not valid, so these are not the points of a right angled triangle.

Case (c)

A = 6 + 4i = (6, 4)

B = 7 + 5i = (7, 5)

C = 8 + 4i = (8, 4)

Use the distance formula to find the distance between two points

$AB = \sqrt{(7-6)^{2}+(5-4)^{2}}=\sqrt{2}$

$BC = \sqrt{(8-7)^{2}+(4-5)^{2}}=\sqrt{2}$

$CA = \sqrt{(8-6)^{2}+(4-4)^{2}}=\sqrt{4}$

For the triangle to be right angles triangle

$CA^{2}=BC^{2}+AB^{2}$

Here, it is valid, so these are the points of a right angled triangle.

7 0

3 years ago

Please help asap 25 pts

alukav5142 [94]

Remark

This is much the same as the last inequality that you posted. When it tells you that you have 1 condition that is more than and one condition that is less than, then you need a compound statement. One of A and B is correct. C or D never will be.

At Least 4

This is the more than condition. You need 4 or more pennies to add to the collection. The rule is the same. The pointy end always points towards the smallest amount

4 ≤ x

No more than 2

That means that you can have 2 or under. The pointy end points to the x

2 ≥ x The biggest number (open end of the arrow) points at the 2.

Answer

2 ≥ x or 4 ≤ x That means the answer is A

8 0

4 years ago

If f(x) = 5x, what is f–1(x)?

skelet666 [1.2K]

Answer:

$f^{-1} (x)=\frac{1}{5}x$

Step-by-step explanation:

we have

$f(x)=5x$

Let

y=f(x)

$y=5x$

Exchange the variables x for y and y for x

$x=5y$

isolate the variable y

$y=x/5$

Let

$f^{-1} (x)=y$

$f^{-1} (x)=\frac{1}{5}x$

8 0

3 years ago

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