I think B should be the answer
You can take the log of the left and right hand side, and then apply the <span>logarithm rules:
log(a</span>ˣ) = x·log(a)
log(ab) = log(a) + log(b)
log(9^(x-1) * 2^(2x+2)) = log(6^(3x))
log(9^(x-1)) + log(2^(2x+2)) = 3x log(6)
(x-1) log(9) + (2x+2) log(2) - 3x log(6) = 0
x(log9 + 2log2 - 3log6) = log9 - 2log2
x = (log9 - 2log2) / (log9 + 2log2 - 3log6)
simplifying by writing log9 = 2log3 and log6 = log2+log3
x= 2(log3 - log2) / (2log3 + 2log2 - 3log2 - 3log3) =
x= -2(log3 - log2) / (log3 + log2) = -2 log(3/2) / log(6)
So 6^x = 4/9
Answer:
From 3 to 6 seconds, the rocket is falling 11 yards per second.
Step-by-step explanation:
Normal pace of progress is exactly the same thing as the slant. Since this is explanatory, we can't track down the specific pace of progress as we could if this were a straight capacity. Be that as it may, we can utilize a similar thought. At the point when t = 3, h(t) = 33, so the organize point is (3, 33). At the point when t = 6, h(t) = 0, so the facilitate is (6, 0). Attachment those qualities into the incline recipe:
m= 0-33/6-3 and m=-33/3 which is 11
From 3 to 6 seconds, the rocket is falling 11 yards each second.
Brainliest?
