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Answer:
-5/4 +i(√2)/4 and -5/4 -i(√2)/4
Step-by-step explanation:
I find simplest form to be easier to get to if the leading coefficient is 1. Dividing by 16, we have ...
x^2 +5/2x +27/16 = 0
Completing the square by adding and subtracting the square of half the x-coefficient, we get ...
(x^2 +5/2x +25/16) +27/16 -25/16 = 0
(x +5/4)^2 = 2/16
Subtracting 2/16, taking the square root, and subtracting 5/4 gives ...
x +5/4 = ±√(-2/16)
x = -5/4 ±i(√2)/4
The roots are -5/4 +i(√2)/4 and -5/4 -i(√2)/4.
Answer:
the midpoint of it is 8,-6
Step-by-step explanation:
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Answer: A is the correct option.Segment AD is 3 and segment AE is 2.
Step-by-step explanation:
Given : A triangle ABC where AC=4 and AB=6
then to prove segment DE is parallel to segment BC and half its length.
the length of AD and AE must divide AC and AB respectively to get the same ratio of 2:1
To apply converse of basic proportionality theorem.
If we take first option Segment AD is 3 and segment AE is 2 then

Therefore by converse of basic proportionality theorem
DE is parallel to segment BC and half its length.
Therefore A is correct option.
Answer:
please mark as brainlist answers
The y intercept is 3
You can also say that the y intercept is at (0,3) which is a more detailed answer. However saying "y intercept is 3" is sufficient enough because the x coordinate of the y intercept is always x = 0.
The y intercept is the location where the graph crosses or touches the y axis. This is at the halfway point between the 2 and 4, so (2+4)/2 = 6/2 = 3