What's the gcf for x^3 y^2 and xy^5

Mathematics

2 answers:

Crazy boy [7]2 years ago

8 0

Xy^2 is the answer to this!

defon2 years ago

7 0

<h3>Answer: xy^2</h3>

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Explanation:

We can rewrite x^3y^2 into x*x^2*y^2

We can rewrite xy^5 into x*y^2*y^3

Note how x*x^2*y^2 and x*y^2*y^3 both have an x in common. So that means x is part of the GCF.

Similarly, x*x^2*y^2 and x*y^2*y^3 have y^2 in common as well.

Overall, both original expressions contain x and y^2 which leads to the overall GCF being xy^2

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makkiz [27]

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6 0

3 years ago

I need help asap pls and thank you ;)

olga55 [171]

Answer:

$\text{Length of AB is }\frac{ah}{a+h}$

Step-by-step explanation:

Given △KMN, ABCD is a square where KN=a, MP⊥KN, MP=h.

we have to find the length of AB.

Let the side of square i.e AB is x units.

As ADCB is a square ⇒ ∠CDN=90°⇒∠CDP=90°

⇒ CP||MP||AB

In ΔMNP and ΔCND

∠NCD=∠NMP (∵ corresponding angles)

∠NDC=∠NPM (∵ corresponding angles)

By AA similarity rule, ΔMNP~ΔCND

Also, ΔKAP~ΔKPM by similarity rule as above.

Hence, corresponding sides are in proportion

$\frac{ND}{NP}=\frac{CD}{MP} \thinspace\thinspace and\thinspace\thinspace \frac{KA}{KP}=\frac{AB}{PM} \\\\\frac{ND}{NP}=\frac{x}{h} \thinspace\thinspace and\thinspace\thinspace \frac{KA}{KP}=\frac{x}{h}\\\\\frac{NP}{ND}=\frac{h}{x} \thinspace\thinspace and\thinspace\thinspace \frac{KP}{KA}=\frac{h}{x}\\\\\frac{PD}{ND}=\frac{h}{x}-1 \thinspace\thinspace and\thinspace\thinspace \frac{AP}{KA}=\frac{h}{x}-1\\$