3 years ago

Help me solve question no.1No spammers Only correct answerer

Mathematics

1 answer:

OleMash [197]3 years ago

3 0

Answer:

hi hope this helps you

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tatyana61 [14]

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

a(t)=(t−k)(t−3)(t−6)(t+3) is a polynomial function of tt, where kk is a constant. Given that a(2)=0a(2)=0, what is the absolute

Crank

Since $a(2)=0$ , we know that $t-2$ must be a factor of $a(t)$ , so $k=2$ . Then the zeros of $a(t)$ are $t=2,3,6,-3$ , and their product is -108, whose absolute value is 108.

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3 years ago

Help me solve question no.1No spammers Only correct answerer​

Help me solve question no.1No spammers Only correct answerer