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sergij07 [2.7K]

2 years ago

7

For two days, your boss decides to double the amount you make if on day 1, you make $70 dollars and on day 2, you make$80 dollar

s, write an expression for the total commission you earn?

1 answer:

Hoochie [10]2 years ago

6 0

Answer:

300

Step-by-step explanation:

Day 1: $70

Day 2: $80

Total commission = day 1 × 2 + day 2 × 2

= 70 × 2 + 80×2

= 140 + 160

= 300

Or

Total commission = 2(day 1 + days 2)

= 2(70 + 80)

= 2(150)

x = 300

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Two poles 8m and 13m high

Brilliant_brown [7]

Answer:

13 m

Step-by-step explanation:

<u>The distance x is:</u>

x = √12² + (13 -8)² = √144 + 25 = √169 = 13 m

6 0

3 years ago

Which applies the power of a product rule to simplify (5 t) cubed?

Elena L [17]

Answer:

(5 t ) cubed = 5 cubed . t cubed = 125 t cubed applies the power of a product rule to simplify (5 t) cubed ⇒ 3rd answer

Step-by-step explanation:

Let us revise some rules of exponents

$a^{m}$ × $a^{n}$ = $a^{m+n}$

$a^{m}$ ×÷ $a^{n}$ = $a^{m-n}$

$(a^{m})^{n}$ = $a^{m.n}$

$(a.b)^{m}$ = $a^{m}$ . $b^{m}$

To simplify $(5t)^{3}$

∵ 5t means 5 × t

∵ Both of them are cubed

- Use the 4th rule above

∴ $(5t)^{3}$ = $(5)^{3}.(t)^{3}$

∵ (5)³ = 5 × 5 × 5 = 125

∴ $(5t)^{3}$ = $(5)^{3}.(t)^{3}$ = 125 t³

(5 t ) cubed = 5 cubed . t cubed = 125 t cubed applies the power of a product rule to simplify (5 t) cubed

3 0

3 years ago

Read 2 more answers

Valeria has a new beaded necklace. 18 out of the 20 beads on the necklace are blue. What percentage of beads on Valeria's neckla

ANTONII [103]

Answer:

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6 0

3 years ago

Read 2 more answers

PLEASE HELP! The table shows the number of championships won by the baseball and softball leagues of three youth baseball divisi

Irina18 [472]

Answer:

Question 1: $P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16}}{ \frac{4}{16}} = \frac{1}{2}$

Question 2:

A. $P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

B. $P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

C. $P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

Step-by-step explanation:

Conditional probability is defined by

$P(A|B)= \frac{P(A and B)}{P(B)}$

with P(A and B) beeing the probability of both events occurring simultaneously.

Question 1:

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16} }{ \frac{4}{16} } = \frac{1}{2}$

Question 2.A:

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

Question 2.B:

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( Z and B)= \frac{ 1 }{ 16 }[/tex]

By definition,

$P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

Question 3.B

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

then

$P (Y or Z) = P(Y) + P(Z) = \frac{6}{16}$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

so

$P((YorZ) and B)= \frac{3}{16}$

By definition,

$P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

3 0

3 years ago

For every 4 basketballs there are 5 baseballs what is the ratio

77julia77 [94]

The answer would be 4:5 because they said basketballs first

7 0

3 years ago