Let p be the probability of success, p = 0.4.
Pr[2 success] = nC2 * p^2 * (1-p)^3 = 0.346
Pr[3 success] = nC3 * p^3 * (1-p)^2 = 0.230
Pr[4 success] = nC4 * p^4 * (1-p)^1 = 0.077
So, the probability of getting 2, 3, or 4 success, would be 0.356 + 0.230 + 0.077 = 0.663, alternatively, 66.3%.
Answer:
169
Step-by-step explanation:

It is a rhombus, so u only need to square 13
Answer:
b
Step-by-step explanation:
Answer:
A (2,3); B (5, 2.5) C: (.5, -1.5)
Step-by-step explanation:
divide everything by 2