The preimage of a triangle has points A(4,6) B(10,5) and C(1,-3). What are the coordinate of the image after a dilation of 1/2?

Frank created a circle graph to show how he spent his time one day. He spent 8 hours at school, 8 hours sleeping, and the rest o

Valentin [98]

If there are 24 hours a day, he hangs out 8 hours a day since 24-8-8=16

All activities are eqyal to 8/24, which simplifies to 1/3.

1/3 as a percent is 33.33...%

He should include 33.33..% three times in his circle graph.

3 0

3 years ago

Read 2 more answers

If a function is written in slope intercept form, y=mx+b, the x represents the ______.

Hitman42 [59]

The x in y = mx + b represents the input, C.

4 0

3 years ago

The process standard deviation is 0.27, and the process control is set at plus or minus one standard deviation. Units with weigh

mr_godi [17]

Answer:

a) $P(X$

And for the other case:

tex] P(X>10.15)[/tex]

$P(X>10.15)= P(Z > \frac{10.15-10}{0.15}) = P(Z>1)=1-P(Z$

So then the probability of being defective P(D) is given by:

$P(D) = 0.159+0.159 = 0.318$

And the expected number of defective in a sample of 1000 units are:

$X= 0.318*1000= 318$

b) $P(X$

And for the other case:

tex] P(X>10.15)[/tex]

$P(X>10.15)= P(Z > \frac{10.15-10}{0.05}) = P(Z>3)=1-P(Z$

So then the probability of being defective P(D) is given by:

$P(D) = 0.00135+0.00135 = 0.0027$

And the expected number of defective in a sample of 1000 units are:

$X= 0.0027*1000= 2.7$

c) For this case the advantage is that we have less items that will be classified as defective

Step-by-step explanation:

Assuming this complete question: "Motorola used the normal distribution to determine the probability of defects and the number of defects expected in a production process. Assume a production process produces items with a mean weight of 10 ounces. Calculate the probability of a defect and the expected number of defects for a 1000-unit production run in the following situation.

Part a

The process standard deviation is .15, and the process control is set at plus or minus one standard deviation. Units with weights less than 9.85 or greater than 10.15 ounces will be classified as defects."

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

$X \sim N(10,0.15)$

Where $\mu=10$ and $\sigma=0.15$

We can calculate the probability of being defective like this:

$P(X$

And we can use the z score formula given by:

$z=\frac{x-\mu}{\sigma}$

And if we replace we got:

$P(X$

And for the other case:

tex] P(X>10.15)[/tex]

$P(X>10.15)= P(Z > \frac{10.15-10}{0.15}) = P(Z>1)=1-P(Z$

So then the probability of being defective P(D) is given by:

$P(D) = 0.159+0.159 = 0.318$

And the expected number of defective in a sample of 1000 units are:

$X= 0.318*1000= 318$

Part b

Through process design improvements, the process standard deviation can be reduced to .05. Assume the process control remains the same, with weights less than 9.85 or greater than 10.15 ounces being classified as defects.

$P(X$

And for the other case:

tex] P(X>10.15)[/tex]

$P(X>10.15)= P(Z > \frac{10.15-10}{0.05}) = P(Z>3)=1-P(Z$

So then the probability of being defective P(D) is given by:

$P(D) = 0.00135+0.00135 = 0.0027$

And the expected number of defective in a sample of 1000 units are:

$X= 0.0027*1000= 2.7$

Part c What is the advantage of reducing process variation, thereby causing process control limits to be at a greater number of standard deviations from the mean?

For this case the advantage is that we have less items that will be classified as defective

5 0

3 years ago

Frequent food questionnaires (FFQ) are a simple way to obtain information on the foods individuals consume by asking them questi

Ilia_Sergeevich [38]

Answer:

Asnwer is A

Step-by-step explanation:

since the correlation between the FFQ and DR is 0.89

x y xy $x^{2}$ $y^{2}$

8.26 1.68 13.8768 68. 2276 2.8224

0.83 0 0 06889 0

20.13 15.1 303.963 405.2169 228.01

11.16 7.49 83.5884 124.5456 56.1001

7.18 12.84 92.1912 51.5524 164.8656

1.76 0 0 3.0976 0

22.46 25.06 567.8596 513.4756 628.0036

-----------------------------------------------------------------------------------------------------------

∑ $x_{i}$ = ∑ $y_{i}$ = ∑ $x_{i} y_{i}$ = ∑ $x_{i}^{2} y_{i}^{2}$ = ∑ $y_{i} ^{2}$ =

71.98 62.17 1061.479 1166.8046 1079.8017

-------------------------------------------------------------------------------------------------------------

Correlation Coefficient or Pearson Correlation is given by:

the rest calculation is in the attached image

3 0

3 years ago

PLEASEEE I NEED HELPPP!!!!

taurus [48]

Answer:

#carry on learning

mark me as brainliest

Find a point-slope form for the line that satisfies the stated conditions. Slope , passing through (-5,4)

I really need this question answered

By:

I don't see a value for the slope. We need that to set the equation, otherwise I can write an unlimited number of equations that pass through (-5,4).

I'll assume a slope so that you can see how the procedure would work. I like 6, so we'll assume a slope of 6.

The equation for a straight line has the form y = mx + b, where m is the slope and y is the y-intercept, the value of y when x = 0. We want a line that has slope 6, so:

y = 6x + b

We need to find b, so substitute the point (-5,4) that we know is on the line:

4 = 6*(-5) + b and solve for b

4 = -30 + b

b = 34

The line is y = 6x + 34

4 0

2 years ago