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Angelina_Jolie [31]
3 years ago
13

How to find the slope.

Mathematics
1 answer:
Feliz [49]3 years ago
8 0
It’s undefined, it just going up and down

finding slope is rise over run when it’s like this / \ if it like this | it just undefined if it goes like this _ it’s 0
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Anybody know the right answer?
qwelly [4]

Quadrant I : cot(x) > 0 → -cot(x) < 0

Quadrant II : cot(x) < 0 → -cot(x) > 0

Quadrant III : cot(x) > 0 → -cot(x) < 0

Quadrant IV : cot(x) < 0 → -cot(x) > 0

------------------------------------------------------------------

a)\ \left(\dfrac{11\pi}{6},\ -\sqrt3\right)\\\\\dfrac{11\pi}{6}\in\text{Quadrant IV, then -cot(x)} > 0,\ \text{we have}\ -\cot\dfrac{11\pi}{6}=-\sqrt3 < 0

Answer: a)

b)\\\dfrac{2\pi}{3}\in\text{Quadrant II},\ -\cot(x) > 0,\ \text{we have}\ \dfrac{\sqrt3}{3} > 0\\\\c)\\\dfrac{5\pi}{4}\in\text{Quadrant III},\ -\cot(x) < 0,\ \text{we have}\ -1 < 0\\\\d)\\\dfrac{4\pi}{3}\in\text{Quadrant III},\ -\cot(x) < 0,\ \text{we have}\ -\dfrac{\sqrt3}{3} < 0

We know that one answer is only true, so we did not check the correctness of the cotangent value, only to the number sign

8 0
3 years ago
What is .63 converted into a decimal?
nadezda [96]

Answer: 63 as a decimal is 0.63

Step-by-step explanation:

3 0
3 years ago
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Solve the equation<br> -3x + 1 + 10x = x + 4<br> 0 x = 1/2<br> х<br> =<br> x = 12<br> X = 18
pav-90 [236]

Answer:

<h3>            x = 1/2</h3>

Step-by-step explanation:

-3x + 1 + 10x = x + 4

      -1                  -1

        7x  = x  + 3  

       -x          -x

        6x = 3

      ÷6      ÷6

         x = 1/2

8 0
3 years ago
The result of 6 subtracted from a number n is at least 2. Which inequality represents this situation? A.
anygoal [31]
It had to be B


because 6 is subtracted by the number n and the only one that has n-6/ 6-n is B
3 0
4 years ago
dylan invested $600 in a savings account at a 2% annual interest rate. He made no deposits or withdrawals on the account for 2 y
Ksivusya [100]

Answer:

He's RICH

Step-by-step explanation:

100,566

4 0
3 years ago
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