Answer:
24.56 (parallelogram)
Step-by-step explanation:
4 sides of ABCD: AB, BC, AD, DC
perimeter = AB + BC + AD + DC
distance of two points: √(x-x')²+(y-y')²
AB = √3²+4² = √25 = 5
BC = √7²+2² = √53 = 7.28
AD = √7²+2² = √53 = 7.28
DC = √3²+4² = √25 = 5
P = 5*2 + 7.28*2 = 24.56
Answer:
D. (-∞,4]
Step-by-step explanation:
The range is the y values
The lowest y values is negative infinity
The highest y values is 4
( - inf, 4]
We use the parentheses since we cannot get to negative infinity, the bracket since we reach 4
X³ - 12x² + 35x
x(x² - 12x + 35)
x(x-5)(x-7)
Answer:
Step-by-step explanation:
Since the inscribed angle theorem tells us that any inscribed angle will be exactly half the measure of the central angle that subtends its arc, it follows that all inscribed angles sharing that arc will be half the measure of the same central angle. Therefore, the inscribed angles must all be congruent.
Answer:
- sin C=h/a
- substitution property of equality
- commutative property of multiplication
Step-by-step explanation:
Because two points determine a line, you can draw altitude BD perpendicular to AC with height h. By the definition of a sine ratio, <u>sin(C) = h/a</u>, which can be rearranged into a·sin(C) = h. The area of △ABC is A=1/2bh. The <u>substitution property of equality</u> can be used to write A=1/2b(a sinC), which becomes A=1/2ab(sinC) by the <u>commutative property of multiplication</u>.
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The mnemonic SOH CAH TOA reminds you that the sine ratio is ...
Sin = Opposite/Hypotenuse
Here, the side of the right triangle opposite angle C is designated "h", the height of ∆ABC. The hypotenuse of that right triangle is side "a". So ...
sin(C) = h/a
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The substitution property of equality lets you replace any expression with its equal. Here, we have h=a·sin(C), so we can use a·sin(C) in place of h in the formula for triangle area:
1/2bh = 1/2ba·sin(C)
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The commutative property of multiplication lets you rearrange the order of the factors in a product, so ...
ba = ab
and
A = 1/2ba·sin(C) = 1/2ab·sin(C)
