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Lelu [443]
3 years ago
10

Do I have the right answer?

Mathematics
1 answer:
Vsevolod [243]3 years ago
3 0
Yes, I think I’m not sure correct me if I’m wrong .
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AYUDAAA PORFAVOOOOOOR!!
galben [10]

Answer:

4

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Find the upper bound for 96.3cm measured to the nearest tenth of a cm
Zarrin [17]

Answer:

100cm

Step-by-step explanation:

Will be 100cm as when approximated to tenth

Tenth of cm or any other measure it must ends with 10 or zeroz digit that is 20,30 or 97be 100

8 0
3 years ago
Which choice is equivalent to the expression below when y2 0?<br> √y^2 + √16y^3 – 4y√y
DanielleElmas [232]

Answer:

Option C.

Step-by-step explanation:

We start with the expression:

\sqrt{y^3}  + \sqrt{16*y^3} - 4*y\sqrt{y}

where y > 0. (this allow us to have y inside a square root, so we don't mess with complex numbers)

We want to find the equivalent expression to this one.

Here, we can do the next two simplifications:

\sqrt{16*y^3} = \sqrt{16} \sqrt{y^3} = 4*\sqrt{y^3}

And:

y*\sqrt{y} = \sqrt{y^2} *\sqrt{y} = \sqrt{y^2*y} = \sqrt{y^3}

If we apply these two to our initial expression, we can rewrite it as:

\sqrt{y^3}  + \sqrt{16*y^3} - 4*y\sqrt{y}

\sqrt{y^3}  + 4*\sqrt{y^3} - 4\sqrt{y^3} = \sqrt{y^3}

Here we can use the second simplification again, to rewrite:

\sqrt{y^3} = y*\sqrt{y}

So, concluding, we have:

\sqrt{y^3}  + \sqrt{16*y^3} - 4*y\sqrt{y} = y*\sqrt{y}

Then the correct option is C.

8 0
3 years ago
AYO PLEASE HELP ILL GOVE YOU BRAINLIEST
tamaranim1 [39]

it's a i think, hope this helps

6 0
2 years ago
SOMEONE HELP ME BRO I NEED DA ANSWER
cupoosta [38]

I think that would be 0.202. ( Sorry if i'm wrong )

Hope helps?-aparri

6 0
3 years ago
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