Answer:
Step-by-step explanation:
Here, you can use a simple formula.
To find the point of intersection you just put x=0 or y=0.
Because, if a graph intersects x-axis, then at this point y=0
Similarly, if a graph intersects y-axis, then at this point x=0
So, for our given line.
y=-1/4 x +2
when , x=0 , y=-1/4 (0)+2=2
So, the graph intersects y-axis at y=2
when , y=0 ,
then 0=-1/4 x+2
or, 1/4 x=2
or, x=8 [multiplying by 4]
So, the graph intersects x-axis at x=8
90
55.8 /? = 62/100
55.8 x 100= 62 x ?
5580=62 x ?
5580/62 = ?
?=90
Answer:

Step-by-step explanation:
As the triangles are similar :
45/55 = (12x - 3)/143
9/11 = (12x - 3)/143
9 x 13 = 12x - 3
12x = 117 + 3
12x = 120
x = 10
First, plot the points. Point R would be somewhere in the second Quadrant, point M would be in the first quadrant 1, point B would be in the fourth quadrant, and point S would be on the negative y-axis. A property of rhombi is that their diagonals are perpendicular. One would need to calculate the slopes of the diagonals and determine whether or not they are perpendicular. Lines are perpendicular if and only if their slopes are opposite reciprocals. Example: 2 and -0.5
Formulas needed:
Slope formula:

The figure would look kinda like this:
R
M
S
B
Diagonals are segment RB and segment SM
So, your slope equations would look like this:

and

Slope of RB= -1
Slope of SM=7
Not a rhombus, slopes aren't perpendicular. But this figure may very well be a parallelogram
Answer:
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