Answer:

Step-by-step explanation:

Answer:
Hence, the following equations, when graphed, intersect at the point (4, 0):
x - y = 4 (1)
x + y = 4 (4)
Step-by-step explanation:
<em>" For the graph to intersect at the point (4,0) we mean that when y=0 , x must be equal to 4 or we could say that when x=4 then y=0".</em>
1)
x-y=4
now when y=0 then x=4.
Hence, the graph intersect at the point (4,0).
2)
-x-y=4
When y=0 in the equation then x=-4, Hence the point (4,0) does not lie on the graph of the given function.
3)
2x-y=7
When y=0 then x=7/2.
Hence the graph of the function does not intersect at the point (4,0).
4)
x+y=4
When y=0 then x=4.
Hence the graph of the given function intersect at (4,0).
5)
2x + y = 7
When y=0 then x=7/2.
Hence the graph of the function does not intersect at the point (4,0).
6)
2x + y = -7
When y=0 then x= -7/2.
Hence the graph of the function does not intersect at the point (4,0).
Explication étape par étape:
Compte tenu des expressions ';
A = 4 (x + 5) -8
B = x² + 15
Nous devons vérifier si A = B pour les deux valeurs de x à x = 1 et x = 3
à quand x = 1
A = 4 (1 + 5) -8
A = 4 (6) - 8
A = 24-8
A = 16
B = x² + 15
B = 1² + 15
B = 1 + 15
B = 16
Donc à quand x = 1, A = B = 16
quand x = 3
A = 4 (x + 5) -8
A = 4 (3 + 5) -8
A = 4 (8) - 8
A = 32-8
A = 24
B = 3² + 15
B = 9 + 15
B = 24
Également lorsque x = 3, A = B = 24
Cela montre que le postulat d'Emmas est juste.
Answer:
A is right
B is acute
C is obtuse
D is right
Step-by-step explanation:
90 is right
anything under 90 is acute
over 90 obtuse