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3 years ago

9

What is x-intercept of the line with the equation 4×+2y=12?

2 answers:

iren [92.7K]3 years ago

8 0

3
to solve, plug in 0 for y

4x+2(0)=12
4x=12
x=3

Julli [10]3 years ago

5 0

The X-intercept is a point where the line crosses the X lines. That means it would be the point where Y=0. Then to find the X-intercept you only need to insert Y=0 into the equation. The calculation would be:

<span> 4×+2y=12
4X+ 2 (0)= 12
4X =12
X=12/4 = 3</span>

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lukranit [14]

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Step-by-step explanation:

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3 years ago

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Solve for x: 2|х - 3 |+1 = 7

Rasek [7]

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3 years ago

The average value of a function f over the interval [−2,3] is −6 , and the average value of f over the interval [3,5] is 20. Wha

Xelga [282]

Answer:

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

Step-by-step explanation:

Let suppose that function $f$ is continuous and integrable in the given intervals, by integral definition of average we have that:

$\frac{1}{3-(-2)} \int\limits^{3}_{-2} {f(x)} \, dx = -6$ (1)

$\frac{1}{5-3} \int\limits^{5}_{3} {f(x)} \, dx = 20$ (2)

By Fundamental Theorems of Calculus we expand both expressions:

$\frac{F(3)-F(-2)}{3-(-2)} = -6$

$F(3) - F(-2) = -30$ (1b)

$\frac{F(5)-F(3)}{5-3} = 20$

$F(5) - F(3) = 40$ (2b)

We obtain the average value of $f$ over the interval $[-2, 5]$ by algebraic handling:

$F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)$

$F(5) - F(-2) = 10$

$\frac{F(5)-F(-2)}{5-(-2)} = \frac{10}{5-(-2)}$

$\bar f = \frac{10}{7}$

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

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3 years ago

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vladimir2022 [97]

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3 years ago

1. Isosceles Triangle The two equal sides of an isosceles triangle are each 42

gavmur [86]

Answer:

1. H = 29 cm

2. θ = 44°

Step-by-step explanation:

1. We can find the height of the triangle by considering the isosceles triangle as two right triangles. The height can be found by using Pitagoras:

$L^{2} = H^{2} + B^{2}$

Where:

L: is the sides of the isosceles triangle = 42 cm

B: is the base = 30 cm

H: is the height =?

Then, the height is:

$H = \sqrt{L^{2} - B^{2}} = \sqrt{(42 cm)^{2} - (30 cm)^{2}} = 29.4 cm = 29 cm$

2. The two equal angles (θ) can be found using the following trigonometric identity:

$cos(\theta) = \frac{B}{L}$

$\theta = cos^{-1}(\frac{30 cm}{42 cm}) = 44.4^{\circ} = 44^{\circ}$

Hence, the two equal angles are 44°.

I hope it helps you!

3 0

3 years ago