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meriva
3 years ago
9

What is x-intercept of the line with the equation 4×+2y=12?

Mathematics
2 answers:
iren [92.7K]3 years ago
8 0
3
to solve, plug in 0 for y

4x+2(0)=12
4x=12
x=3
Julli [10]3 years ago
5 0
The X-intercept is a point where the line crosses the X lines. That means it would be the point where Y=0. Then to find the X-intercept you only need to insert Y=0 into the equation. The calculation would be:

<span> 4×+2y=12
4X+ 2 (0)= 12
4X =12
X=12/4 = 3</span>
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Guys im giving max points for this, please give me a correct answer and best gets brainliest.
lukranit [14]

Answer:

y=-2/3 x +4

Step-by-step explanation:

slop = (6-0)/(-3-6)= -2/3

c= 4  (when x =0)

line equation:

y= mx + c

y=-2/3 x +4

4 0
3 years ago
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Solve for x: 2|х - 3 |+1 = 7
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The average value of a function f over the interval [−2,3] is −6 , and the average value of f over the interval [3,5] is 20. Wha
Xelga [282]

Answer:

The average value of f over the interval [-2,5] is \frac{10}{7}.

Step-by-step explanation:

Let suppose that function f is continuous and integrable in the given intervals, by integral definition of average we have that:

\frac{1}{3-(-2)} \int\limits^{3}_{-2} {f(x)} \, dx = -6 (1)

\frac{1}{5-3} \int\limits^{5}_{3} {f(x)} \, dx = 20 (2)

By Fundamental Theorems of Calculus we expand both expressions:

\frac{F(3)-F(-2)}{3-(-2)} = -6

F(3) - F(-2) = -30 (1b)

\frac{F(5)-F(3)}{5-3} = 20

F(5) - F(3) = 40 (2b)

We obtain the average value of f over the interval [-2, 5] by algebraic handling:

F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)

F(5) - F(-2) = 10

\frac{F(5)-F(-2)}{5-(-2)} = \frac{10}{5-(-2)}

\bar f = \frac{10}{7}

The average value of f over the interval [-2,5] is \frac{10}{7}.

4 0
3 years ago
You are designing an aquarium that is to have a tank holding 225,000 gallons of water. The tank will be 100 feet long and 20 fee
vladimir2022 [97]
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5 0
3 years ago
1. Isosceles Triangle The two equal sides of an isosceles triangle are each 42
gavmur [86]

Answer:

1. H = 29 cm

2. θ = 44°

Step-by-step explanation:

1. We can find the height of the triangle by considering the isosceles triangle as two right triangles. The height can be found by using Pitagoras:

L^{2} = H^{2} + B^{2}

Where:

L: is the sides of the isosceles triangle = 42 cm

B: is the base = 30 cm

H: is the height =?

Then, the height is:

H = \sqrt{L^{2} - B^{2}} = \sqrt{(42 cm)^{2} - (30 cm)^{2}} = 29.4 cm = 29 cm

2. The two equal angles (θ) can be found using the following trigonometric identity:          

cos(\theta) = \frac{B}{L}

\theta = cos^{-1}(\frac{30 cm}{42 cm}) = 44.4^{\circ} = 44^{\circ}

Hence, the two equal angles are 44°.

I hope it helps you!  

3 0
2 years ago
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