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Serhud [2]
2 years ago
6

Radio signals travel at a rate of 3x10^8 meters per second how many seconds would it take for a radio signal to travel from a sa

tellite to the surface of the earth if the satellite is orbiting at a height of 3.6x10^7 meters
Mathematics
2 answers:
marshall27 [118]2 years ago
4 0

Answer:

1.2x10^-1 seconds

Step-by-step explanation:

timama [110]2 years ago
4 0

Answer:

0.12 seconds

Step-by-step explanation:

just think - how long does it take you to travel for example 30 km, if you are going 60 km/h ?

you have to divide 30 by 60 and get 0.5 or 1/2. meaning it takes you (logically) 30 minutes or half an hour to do so.

it is the same principle for all these kinds of questions.

we only need to keep an eye on the dimension of what we are talking about. is it hours or seconds ? meters or kilometers ? and do in

we need here to focus on seconds and to calculate

3.6×10⁷ / 3×10⁸ = 3.6 / 3×10¹ = 1.2 / 10 = 0.12 seconds

or

1.2 \times  {10}^{ - 1}

seconds

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3. Dan's credit card was lost on a vacation. He immediately reported it missing. The person who found it days later used it, and
Olenka [21]

The question is an illustration of the Truth in Lending Act, and Dan is responsible for paying $0

<h3>Truth in Lending Act</h3>

The Truth in Lending Act is simply an act that protects people from unfair charges on their credit cards, especially in case of theft and card misplacement.

<h3>The scenarios</h3>

From the question, we have the following scenarios

  • His card got lost
  • He reported
  • Someone else saw the card and purchased goods worth over $200

Because Dan reported when his card got lost, he is protected by the Truth in Lending Act (TILA).

Hence, Dan is responsible for paying $0

Read more about the Truth in Lending Act at

brainly.com/question/1979208

4 0
2 years ago
Recall that a 6-bit string is a bit strings of length 6, and a bit string of weight 3, say, is one with exactly three 1's. How m
strojnjashka [21]

Answer:

1.. Total number of 6 bit strings is 64

2. Number of 6-bit strings with weight of 0 is 1

3. Number of 6-bit strings with weight of 1 is 6

4. Number of 6-bit strings with weight of 3 is 20

5. Number of 6-bit strings with weight of 5 is 6

6. Number of 6-bit strings with weight of 6 is 1

7. Number of 6-bit strings with weight of 7 is 0

Step-by-step explanation:

A bit string is a string that contains 0 and 1 only

1. Total number of 6 bit strings is 2^6 = 64

2. Number of 6 bit strings with weight 0 is 1

Explanation

Weight 0 means a string with no occurrence of 1

Here, we are only interested in occurrence and not order of occurrence

We apply combination formula for this

nCr = n!/(n-r)!r!

n = 6 and r = 0 i.e. no occurrence of 1

6C0 = 6!/(6-0)!0!

6C0 = 6!/6!0!

6C0 = 1

Hence, the number of string with weight 0 (i.e. no occurrence of 1 ) is 1

3. Number of string with weight 1 is 6

Explanation

Weight 0 means a string with exactly 1 occurrence of '1'

Here, we are only interested in occurrence and not order of occurrence

We apply combination formula for this

nCr = n!/(n-r)!r!

n = 6 and r = 1

6C1 = 6!/(6-1)!1!

6C1 = 6!/5!1!

6C1 = 6

Hence, the number of string with weight 6

4. Number of string with weight 3 is 20

Explanation

n = 6 and r = 3

6C3 = 6!/(6-3)!3!

6C3 = 6!/3!3!

6C3 = 20

Hence, the number of string with weight 3 is 20

5. Number of string with weight 5 is 6

Explanation

n = 6 and r = 5

6C5 = 6!/(6-5)!5!

6C5 = 6!/1!5!

6C5 = 6

Hence, the number of string with weight 5 is 6

6. Number of string with weight 6 is 1

Explanation

n = 6 and r = 6

6C6 = 6!/(6-6)!6!

6C6 = 6!/0!6!

6C6 = 1

Hence, the number of string with weight 6 is 1

7. Number of string with weight 7 is 0

Weight of 7 means that a string that has 7 occurrence of 1

The total length of a 6 bit is 6

Since 6 is less than 7, there's no way a bit of weight 7 can occur.

So, the right answer for this is 0.

8 0
2 years ago
Solve the following: S5 for 600 + 300 + 150 + .
Tresset [83]
600 + 300 + 150 + . . . is a geometric sequence with a = 600 and r = 1/2
Sn = a(1 - r^n)/(1 - r)
S5 = 600(1 - (1/2)^5)/(1 - 1/2) = 600(1 - 1/32)/(1/2) = 1,200(31/32) = 1,162.5
8 0
3 years ago
• A research scientist measures the outside temperature, in degrees Fahrenheit, at various
polet [3.4K]

Answer:

{t|60 <= t <= 85}

Step-by-step explanation:

The temperatures were measures at different times, but does not stop the values being real numbers (i.e. not discrete, or integer values).

So the range of the function is the set of all values between the minimum and maximum measured during the measuring interval (domain) of hours two and twenty-two.

The minimum value = 60F

The maximum value = 85F

So the interval of the range is [60,85], in interval notation.

In set-builder notation, it is

{t|60 <= t <= 85}

5 0
2 years ago
Lesson 5 compare and order rational numbers
devlian [24]

Answer:

Step-by-step explanation:

2/3 4/6 3/8

7 0
3 years ago
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