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Serhud [2]
3 years ago
6

Radio signals travel at a rate of 3x10^8 meters per second how many seconds would it take for a radio signal to travel from a sa

tellite to the surface of the earth if the satellite is orbiting at a height of 3.6x10^7 meters
Mathematics
2 answers:
marshall27 [118]3 years ago
4 0

Answer:

1.2x10^-1 seconds

Step-by-step explanation:

timama [110]3 years ago
4 0

Answer:

0.12 seconds

Step-by-step explanation:

just think - how long does it take you to travel for example 30 km, if you are going 60 km/h ?

you have to divide 30 by 60 and get 0.5 or 1/2. meaning it takes you (logically) 30 minutes or half an hour to do so.

it is the same principle for all these kinds of questions.

we only need to keep an eye on the dimension of what we are talking about. is it hours or seconds ? meters or kilometers ? and do in

we need here to focus on seconds and to calculate

3.6×10⁷ / 3×10⁸ = 3.6 / 3×10¹ = 1.2 / 10 = 0.12 seconds

or

1.2 \times  {10}^{ - 1}

seconds

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El área de un rectángulo se calcula multiplicando la longitud de la base por la longitud de la altura. La base del rectángulo mi
NemiM [27]

Answer:

the height of the rectangle is 13 cm

Step-by-step explanation:

The computation of the height of the rectangle is shown below:

As we know that

Area of rectangle =  base × height

156 cm^2 = × 12 × height

So, the height is

= 156 ÷ 12

= 13 cm

hence, the height of the rectangle is 13 cm

7 0
3 years ago
Esme read 12 pages from her science book last night, and it took her 18 minutes. How long will it take her to read tonight's hom
aniked [119]
It should take 45 minutes.  18/12=1.5 
30 times 1.5 is 45
5 0
3 years ago
How do you find the quadratic function with vertex (-2,5) and point (0,9)?
Anastaziya [24]

Answer: y = (x +2)² + 5

<u>Step-by-step explanation:</u>

y = a(x - h)² + k <em>where "a" is the leading coefficient and (h, k) is the vertex</em>

Since we don't know "a", we need to plug in the point (x, y) and the vertex (h, k) to solve for "a":  (x, y) = (0, 9) and (h, k) = (-2, 5)

y = a(x - h)² + k

9 = a(0 - (-2))² + 5

9 = a(0 + 2)² + 5

9 = a(2)² + 5

<u>-5 </u>   <u>          -5 </u>

4  =  a(4)

<u>÷4 </u>   <u> ÷4   </u>

 1 = a

Next, plug in "a" and the vertex (h, k):

y = a(x - h)² + k

y = 1(x +2)² + 5

y = (x +2)² + 5


6 0
4 years ago
What is the solution to the following system of equations?
Degger [83]

Answer:

(3,2)

Step-by-step explanation:

Make sure you use substitution to solve the equation for either x or y first. Then once you have the value of one, plug it into the equation to solve for the value of the other.

8 0
4 years ago
Read 2 more answers
Explain why the square root of -64 is undefined but the cubed root of -64 is defined in the real number system
sergejj [24]
Because there is no number that could be multiplied BY ITSELF and still be negative:
-2 x -2 = 4
2 x 2 = 4
But, cubed root works because a negative can be three times and still be negative:
-4 x -4 x -4 = -64
Hope this helps!
5 0
4 years ago
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