Radio signals travel at a rate of 3x10^8 meters per second how many seconds would it take for a radio signal to travel from a sa
tellite to the surface of the earth if the satellite is orbiting at a height of 3.6x10^7 meters
2 answers:
Answer:
1.2x10^-1 seconds
Step-by-step explanation:
Answer:
0.12 seconds
Step-by-step explanation:
just think - how long does it take you to travel for example 30 km, if you are going 60 km/h ?
you have to divide 30 by 60 and get 0.5 or 1/2. meaning it takes you (logically) 30 minutes or half an hour to do so.
it is the same principle for all these kinds of questions.
we only need to keep an eye on the dimension of what we are talking about. is it hours or seconds ? meters or kilometers ? and do in
we need here to focus on seconds and to calculate
3.6×10⁷ / 3×10⁸ = 3.6 / 3×10¹ = 1.2 / 10 = 0.12 seconds
or

seconds
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E = 3(6^2)
E = 3(36)
And your answer is E = 108 :)
Answer:
3.6 units (nearest tenth)
Step-by-step explanation:
distance formula
= 
Thus, distance between the 2 points
= √[(5 - 3)² + (1 - 4)²]
= √[ 2²+ ( - 3)²]
= √13
= 3.6 units (nearest tenth)
Answer:
-5/4
Step-by-step explanation:
4x=-5
x=-5/4
Answer:
Length = 45 inches and Width = 20 inches
Step-by-step explanation:
Let the width be w.
Length(l)=2.25w
Area = 900 in^2
The formula for the area of a rectangle is Area = length * width
So substituting our values we get:

So we get width = 20 inches
Length = 2.25w
so Length= 2.25*20
=45 inches
Answer:
1536
Step-by-step explanation:
12 x 8 x 4 x 4
(might be wrong)