F(x)=1.2(7)+5
F(x)=8.4+5
F(x)=13.4
So the answer is $13.40
.hello :
an equation of the circle <span>Center at the w(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : r = 1
</span><span>The points (-18,15) and (-20,15) lie on a circle with a radius of 1:
</span>(-18-a)²+(15-b)² = 1 ....(1)
(-20-a)² +(15-b)² = 1 ....(2)
solve this system :
(1) -(2) : (-18-a)² - (-20-a)² =0
(-18-a)² =(-20-a)² =0
( -18-a = -20-a) or (-18-a = - (-20-a))
1 ) ( -18-a = -20-a) no solution confused : -18=-20
2 ) -18-a =20+a
-2a =38
a = -19
subst in (1) :(-18+19)²+(15-b)² =1
(15-b)² = 0.... 15-b = 0 .... b = 15
the center is :w(-19,15)
Answer:
3^5
Step-by-step explanation:
becuase 3*3*3*3*3
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Step-by-step explanation:
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Answer:
x = 3
Step-by-step explanation:
It should NOT be "fight of the origin", rather "right of the origin".
Now let's move on to solve the question...
The x-intercept is found by setting the function equal to 0. Thus:
0 = x^3 - 9x
<em>Let's solve this using algebra:</em>
<em>
</em>
<em />
<em>Hence, x = -3 and x = 3</em>
<em />
The coordinate that is to the right of the origin is the positive one, so x = 3 is the x-intercept we are looking for.
