b
b/c when it's rearranged large to small
Answer: 22, 38
3, 7
8, 12
<u>Step-by-step explanation:</u>
It is given that the PERIMETER is BETWEEN 22 and 38
--> 22 < P < 38
Perimeter = 2w + 2L
It is given that L = w + 5
Substitute P with 2w + 2L and substitute L with w + 5
22 < 2w + 2(w + 5) < 38
22 < 2w + 2w + 10 < 38
12 < 4w < 28
--> 3 < w < 7
Since L = w + 5, then w = L - 5
Substitute P with 2w + 2L and substitute w with L - 5
22 < 2(L - 5) + 2L < 38
22 < 2L + 2L - 10 < 38
32 < 4L < 48
--> 8 < L < 12
Answer: Satisfied for n=1, n=k and n=k+1
Step-by-step explanation:
The induction procedure involves two steps
First is
Basic Step
Here we consider that for the value n=1, there is one car and it will always make the full circle.
Induction Step
Since basic step is satisfied for n=1
Now we do it for n=k+1
Now according to the statement a car makes full circle by taking gas from other cars as it passes them. This means there are cars that are there to provide fuel to the car. So we have a car that can be eliminated i.e. it gives it fuels to other car to make full circle so it is always there.
Now ,go through the statement again that the original car gets past the other car and take the gas from it to eliminate it. So now cars remain k instead of k+1 as it's fuel has been taken. Now the car that has taken the fuel can make the full circle. The gas is enough to make a circle now.
So by induction we can find a car that satisfies k+1 induction so for k number of cars, we can also find a car that makes a full circle.
Answer:
10, 50, 150
Step-by-step explanation:
i just did it lol.
Answer:
72
Step-by-step explanation:
Let the number of candies = n
Tracy ate = 1/3 of n = n/3 remaining 2n / 3
she gave 1/4 of the remainder to her friend = 1/4 of ( n - n/3) = 2n / 12
the new remainder = (2n / 3) - (2n / 12) = n /2
she and her mom then ate altogether = 30
and the brother took from 1 to five, the number he took = x
and she has 3 left
( n/2) - 30 - x = 3
n = 2 ( 33 + x)
now we know that the candies could not be broken and x is between 1 to 5
n = 2 (33 + 1), 2 (33+2), 2(33 +3), 2 (33+ 4) and 2 (33 + 5) this are the possible values of n, ( 68, 70, 72, 74, 76) and the multiple of 3 is 72
n therefore = 72
