Answer:
Anomalous expansion
Explanation:
Anomalous expansion of water is the abnormal way water expands when exposed to low temperature.
At 4 degree Celsius , the density at the top layer is usually at the Maximum which makes the water sinks down and then the water in the lower layer rises up.
When the temperature drops below 4 degree Celsius, the water molecules at the top then freezes leaving the denser molecules at the bottom which doesn’t freeze as a result of their high density.
This way, organisms can survive in the water due to the lower layer not freezing.
Answer:
There won't be any functional viral DNA synthesis
Explanation:
First of all, you must consider that the HSV has a double-stranded, linear DNA genome. Furthermore, the DNA skeleton is made of the 5'-3' phosphodiester bond. In other words, the 5-phosphat of a nucleotide will bond the 3' OH of the Deoxyribose (see image).
Therefore, if you add a molecule which lacks the 3' OH, such as acyclovir, and has a similar chemical structure to a regular nucleotide, the DNA polimerase will be able to add acyclovir to the main backbone of the viral genome. All in all, you'd be ''cheating'' the DNA pol.
Hence, wherever acyclovir was integrated, there won't be any chance to form a 5'-3' phosphodiester bond. The protomolecule will not be stable and will soon be degradated.
seeks to help communities mitigate and adapt to climate change, as well as improve food security.
Answer:
0.0177
Explanation:
Cystic fibrosis is an autosomal recessive disease, thereby an individual must have both copies of the CFTR mutant alleles to have this disease. The Hardy-Weinberg equilibrium states that p² + 2pq + q² = 1, where p² represents the frequency of the homo-zygous dominant genotype (normal phenotype), q² represents the frequency of the homo-zygous recessive genotype (cystic fibrosis phenotype), and 2pq represents the frequency of the heterozygous genotype (individuals that carry one copy of the CFTR mutant allele). Moreover, under Hardy-Weinberg equilibrium, the sum of the dominant 'p' allele frequency and the recessive 'q' allele frequency is equal to 1. In this case, we can observe that the frequency of the homo-zygous recessive condition for cystic fibrosis (q²) is 1/3200. In consequence, the frequency of the recessive allele for cystic fibrosis can be calculated as follows:
1/3200 = q² (have two CFTR mutant alleles) >>
q = √ (1/3200) = 1/56.57 >>
- Frequency of the CFTR allele q = 1/56.57 = 0.0177
- Frequency of the dominant 'normal' allele p = 1 - q = 1 - 0.0177 = 0.9823
The theory of natural selection was first expounded by Charles Darwin and today it is believed to be the main process that brings about evolution.
This process is defined as the process whereby organisms who better adapt to their environment tend to survive and produce more offspring.
Hence, according to this statement, option C is correct.
More organisms are born than can survive.
