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vitfil [10]
3 years ago
12

How do I solve this ?

Mathematics
2 answers:
boyakko [2]3 years ago
8 0
(1,-2) im pretty sure is the answer
Strike441 [17]3 years ago
8 0
(1,2) if I’m not mistaken
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2 8 −10−15÷3=2, start superscript, 8, end superscript, minus, 10, minus, 15, divided by, 3, equals
Sergio039 [100]

Answer:

241

Step-by-step explanation:

Given the equation to evaluate :

2^8 −10−15÷3

2^8 = 256

256 - 10 - 15 ÷ 3

From BODMAS principle, we evaluate the divison before subtraction :

-15 ÷ 3 = - 5

256 - 10 -5

256 - 15

= 241

8 0
3 years ago
How many x-intercepts will the graph of y = 3x2 + 6x + 3 have? (Use the discriminant to
KonstantinChe [14]

Answer:

i think D or B is the answer

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Find the value of f(3) for the function f(x)=-4(x+3) f(3)=
otez555 [7]

Answer:

  • -24

Step-by-step explanation:

<u>Given function</u>

  • f(x)= -4(x+3)

<u>To find</u>

  • f(3)=?

<u>Solution</u>

Substitute x with 3 in the equation to find f(3)

  • f(3) = -4(3+3) = -4*6 = -24
7 0
4 years ago
Given f(x) = 4x^4 find f^-1(x) Then state whether f^-1(x) is a function.
sdas [7]

Answer:

  • f^{-1}(x)=\pm\sqrt[4]{\dfrac{x}{4}}
  • f^{-1}(x) \quad\text{is not a function}

Step-by-step explanation:

To find the inverse function, solve for y:

x=f(y)\\\\x=4y^4\\\\\dfrac{x}{4}=y^4\\\\\pm\sqrt[4]{\dfrac{x}{4}}=y\\\\f^{-1}(x)=\pm\sqrt[4]{\dfrac{x}{4}}

f(x) is an even function, so f(-x) = f(x). Then the inverse relation is double-valued: for any given y, there can be either of two x-values that will give that result.

___

A function is single-valued. That means any given domain value maps to exactly one range value. The test of this is the "vertical line test." If a vertical line intersects the graph in more than one point, then that x-value maps to more than one y-value.

The horizontal line test is similar. It is used to determine whether a function has an inverse function. If a horizontal line intersects the graph in more than one place, the inverse relation is not a function.

__

Since the inverse relation for the given f(x) maps every x to two y-values, it is not a function. You can also tell this by the fact that f(x) is an even function, so does not pass the horizontal line test. When f(x) doesn't pass the horizontal line test, f^-1(x) cannot pass the vertical line test.

_____

The attached graph shows the inverse relation (called f₁(x)). It also shows a vertical line intersecting that graph in more than one place.

5 0
3 years ago
Given that f(x) = 2x2 − 96, find x.
NISA [10]
F(x)=2x(2)−96

Step 1: Add -4x to both sides.

xf+ −4x = 4x−96+ −4x

xf −4x= −96

Step 2: Factor out variable x.

x(f−4)= −96

Step 3: Divide both sides by f-4.

x(f−4)/ f−4 = −96/ f−4

x= −96/f−4

Answer:

x= −96/ f−4

3 0
4 years ago
Read 2 more answers
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