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Sindrei [870]
3 years ago
13

A. Sin40=6/x B. Sin40= x/6 C. Cos40= x/6 D. Cos40=6/x

Mathematics
1 answer:
STatiana [176]3 years ago
7 0
The answer is A. sin40=6/x
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Determine if the lines are parallel, perpendicular, or neither y=5 and y =-1
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Read 2 more answers
Area of a Triangle
jek_recluse [69]

Answer:

3.51 (round to the nearest hundreds)

Step-by-step explanation:

PART A

slope of the line passing through AC : (6-1)/(1-2) = 5/-1 = -5

equation of the line passing through B and perpendicular to AC:

y-3 = 1/5(x-3)

y-3 = 1/5x -3/5

y = 1/5 x - 3/5 + 3

y = 1/5 x + (-3+15)/5

y = 1/5 x + 12/5

PART B

line that passes through the points A and C

y-1 = -5(x-2)

y = -5x+10 + 1

y = -5x + 11

Interception of the lines

y = 1/5x + 12/5

y = -5x + 11

-5x + 11 = 1/5x + 12/5

-25x +55 = x + 12

26x = 43

x = 43/26

y = -5(43/26) + 11

y= -215/26 + 11

y = (-215+286)/26 = 71/26

D (1.65, 2.73)

PART C

AC = \sqrt{(1-2)^2 + (6-1)^2} = \sqrt{1 + 25} = \sqrt{26} = 5,09902

BD = \sqrt{(3-1.65)^2 + (3-2.73)^2} = 1,376735

PART D

AREA = (5,09902 * 1.376735)/2 = 3,509999

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Round 4.9987 to the nearest thousand
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Since it is to the nearest thousand, it would be 4.999
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Answer:

1. 36

2. 16

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