Answer:
Suppose a population of rodents satisfies the differential equation dP 2 kP dt = . Initially there are P (0 2 ) = rodents, and their number is increasing at the rate of 1 dP dt = rodent per month when there are P = 10 rodents.
How long will it take for this population to grow to a hundred rodents? To a thousand rodents?
Step-by-step explanation:
Use the initial condition when dp/dt = 1, p = 10 to get k;

Seperate the differential equation and solve for the constant C.

You have 100 rodents when:

You have 1000 rodents when:

Answer:
256 in²
Step-by-step explanation:
<u><em>Answer:</em></u>
Scott will need 168 ft² of pavers to cover his patio
<u><em>Explanation:</em></u>
Scott wants to cover a trapezoid-shaped patio
<u>This means that:</u>
To get the number of square feet of pavers he'll need, we need to get the area of his patio
<u>Area of trapezium id calculated as follows:</u>

<u>We are given that:</u>
base₁ = 11 ft
base₂ = 13 ft
height = 14 ft
<u>We now substitute with the givens to get the area as follows:</u>

<u>This means that:</u>
Scott will need 168 ft² of pavers to cover his patio
Hope this helps :)
Answer:
6
Step-by-step explanation:
I think so 6 because I think so